Based in this answer I am not able to solve the following question.
Is there a way to vectorize the Value End Of Period (VEoP) column?
import random
import pandas as pd
terms = pd.date_range(start = '2022-01-01', periods=12, freq='YS', normalize=True)
r = pd.DataFrame({
'Return': [1.063, 1.053, 1.008, 0.98, 1.04, 1.057, 1.073, 1.027, 1.025, 1.068, 1.001, 0.983],
'Cashflow': [6, 0, 0, 8, -1, -1, -1, -1, -1, -1, -1, -1]
},index=terms.strftime('%Y'))
r.index.name = 'Date'
r['VEoP'] = 0
for y in range(0,r.index.size):
r['VEoP'].iloc[y] = ((0 if y==0 else r['VEoP'].iloc[y-1]) + r['Cashflow'].iloc[y]) * r['Return'].iloc[y]
r
Return Cashflow VEoP
Date
2022 1.0630 6 6.3780
2023 1.0530 0 6.7160
2024 1.0080 0 6.7698
2025 0.9800 8 14.4744
2026 1.0400 -1 14.0133
2027 1.0570 -1 13.7551
2028 1.0730 -1 13.6862
2029 1.0270 -1 13.0288
2030 1.0250 -1 12.3295
2031 1.0680 -1 12.0999
2032 1.0010 -1 11.1110
2033 0.9830 -1 9.9391
Vectorization is limited when each value relies on the one before it, since it can't be parallelized.
Therefore your for
loop may perform just as well as this "vectorization":
r['VEoP'] = np.frompyfunc(
lambda prev, x: (prev + x.Cashflow) * x.Return,
2, 1, # nin, nout
).accumulate(
[0, *r.to_records()],
dtype=object, # temporary conversion
).astype(float)[1:]
You can read more about np.frompyfunc
and np.ufunc.accumulate
.
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