With the data I have, this R
code x <- t.test(Age ~ Completers, var.equal = TRUE, data = data)
renders the following result:
Two Sample t-test
data: Age by Completers
t = 0.93312, df = 1060, p-value = 0.351
alternative hypothesis: true difference in means between group Completers and group Non Completers is not equal to 0
95 percent confidence interval:
-0.5844018 1.6442118
sample estimates:
mean in group Completers mean in group Non Completers
37.16052 36.63062
What I would like is to plot each mean (found in x$estimate[1]
and x$estimate[2]
) with its own point on the x
axis at its proper height on the y
axis (on the same graph) and each point complemented with the same confidence interval (CI) (found in x$conf.int[1]
and x$conf.int[2]
). Like this[*]:
Unfortunately, if I'm not mistaken, plot()
(from the Generic XY Plotting ) does not seem to handle this. So I tried with plotCI
(from gplots ) as follows:
library(gplots)
plotCI(x = x$estimate[1], y = x$estimate[2],
li = x$conf.int[1], ui = x$conf.int[2])
But it renders as shown below:
My questions:
jmv::
code (see [*]))? [*] Graph obtained with Jamovi Version 2.3.15.0 which uses the following code (but I would like to avoid using jmv::
):
jmv::ttestIS(
formula = Age ~ Completers,
data = data,
plots = TRUE
)
System used:
The following should do what you want, though I dont have the data so may need a bit of tweaking:
Sample data
df <- data.frame(type = c("Completers","Non Completers"),
point_est = c(37.2, 36.8),
ci_lo = c(36.4, 36.0),
ci_hi = c(38.0, 37.5))
Plot
plot(NA, xlim = c(0,3), ylim = c(35, 38), # blank plot
axes = FALSE, xlab = "", ylab = "")
segments(x0 = c(1,2), y0 = df$ci_lo, y1 = df$ci_hi) # add segments
points(df$point_est, pch = 19) # add means
axis(1, at = 0:3, labels = c(NA, df$type, NA)) # add x axis
axis(2) #add y axis
mtext(side = 1, "Completers", padj = 4) # add x label
mtext(side = 2, "Age", padj = -4) # add y label
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