List elements as function arguments Scala

Question

I have a function that takes 5 parameters:

MyFunction(arg1: String, arg2: String, ..., arg5: String)

And a List that has 4 Items

List("a","b","c","d")

I want to simply know how to pass the elements of the list as the 4 first parametres of the function in Scala

Answer 1

The easiest is to use pattern matching (as @LuisMiguelMejíaSuárez proposed in comments)

def myFunction(arg1: String, arg2: String, arg3: String, arg4: String, arg5: String): String = 
  arg1 + arg2 + arg3 + arg4 + arg5

val args = List("a","b","c","d")

val List(a, b, c, d) = args // <-- pattern matching
myFunction(a, b, c, d, "e") // abcde

More exotic way is

import shapeless.syntax.std.function._
import shapeless.syntax.std.traversable._

(myFunction _).toProduct((args :+ "e").toSizedHList(5).get) // abcde