<xsl:copy-of> does not preserve XML tags
Question
Using Saxon HE 11.4 , I'm trying to simply copy some text and preserve XML tags inside of that text. This answer and many others tell me that simply using <xsl:copy-of> is enough. But it doesn't work in my case, <xsl:copy-of> removes all XML tags. Why?
Input XML
<?xml version="1.0" encoding="utf-8"?>
<root>
<card>
<k>а</k>
<body>
<meaning>
<trn>возглас удивления</trn>
<trn>вопрос с оттенком удивления или неудовольствия</trn>
</meaning>
</body>
</card>
</root>
XSLT file
<?xml version="1.0"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:character-map name="escape-square-brackets">
<xsl:output-character character="[" string="\["/>
<xsl:output-character character="]" string="\]"/>
</xsl:character-map>
<xsl:output method="text" encoding="utf-16le" byte-order-mark="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/root">
<xsl:result-document href="/Users/xinatanil/Desktop/compiling stuff/abbyy_udahin_kg_ru.dsl" method="text">
<xsl:text>#NAME "Кыргызско-русский словарь"</xsl:text>
<xsl:text>
</xsl:text>
<xsl:text>#INDEX_LANGUAGE "Russian"</xsl:text>
<xsl:text>
</xsl:text>
<xsl:text>#CONTENTS_LANGUAGE "Russian"</xsl:text>
<xsl:text>
</xsl:text>
<xsl:text>
</xsl:text>
<root>
<xsl:for-each select="card">
<xsl:value-of select="k"/>
<xsl:text>
</xsl:text>
<xsl:for-each select="body/meaning/*">
<xsl:text> </xsl:text>
<xsl:copy-of select="node()"/>
<xsl:text>
</xsl:text>
</xsl:for-each>
<xsl:text>
</xsl:text>
</xsl:for-each>
</root>
</xsl:result-document>
</xsl:template>
</xsl:stylesheet>
Expected output
#NAME "Кыргызско-русский словарь"
#INDEX_LANGUAGE "Russian"
#CONTENTS_LANGUAGE "Russian"
а
<trn>возглас удивления</trn>
<trn>вопрос с оттенком удивления или неудовольствия</trn>
Output that I currently get
#NAME "Кыргызско-русский словарь"
#INDEX_LANGUAGE "Russian"
#CONTENTS_LANGUAGE "Russian"
а
возглас удивления
вопрос с оттенком удивления или неудовольствия
2 answers
solution1
1 2022-12-08 18:54:58
You have used text as your xsl:output method , that way you don't get the copy of element nodes, just the text nodes. So use eg <xsl:output method="xml"/> if your target format is XML and not plain text.
solution2
1 ACCPTED 2022-12-08 20:02:14
Start by changing the main output method to xml and removing it from the xsl:result-document element.
Next, if you want copy the already selected elements that are children of meaning , you need to change:
<xsl:copy-of select="node()"/>
to:
<xsl:copy-of select="."/>
Otherwise you're copying the child nodes of those elements.
And you probably want to remove the root wrapper.
And you will also want to suppress the XML declaration.
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