I am currently having an issue where MySQL is only displaying 1 of my 3 rows in a dynamic Temporary Table I've created in a PHP page. I can confirm how many rows the TmpTable has via:
$numrows = mysqli_num_rows($doResults);
(returns 3)
But when I do my while ($rows=mysqli_fetch_array($doResults)) { }
, only 1 of the 3 rows are returned/displayed. The one row is returned correctly with all fields requested.
Has anyone had any issues with some sort of Caching, etc ... ?
mysqli_fetch_array() returns the next record in the result set, only one record. The name of your variable $row suggests that you expect otherwise. 表明您另有期望。
Try something like
error_reporting(E_ALL); // only for debugging
ini_set('display_errors', 1); // only for debugging
$numrows = mysqli_num_rows($doResults);
echo '<pre>debug: $numrows=', $numrows, "</pre>\n";
$dbgcRow = 0;
while($row=mysqli_fetch_array($doResults)) {
// row counter / number of the current record
echo '<pre>debug: $dbgcRow=', ++$dbgcRow, "</pre>\n";
// print the values of the current record
echo htmlentities(join(',', $row)), "<br />\n";
}
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