How to reference *just* the image part of an image node in Drupal 6

Question

I'm building a recipe management system for a cooking website in Drupal, and I have to say the whole node / view / template thing is working very nicely! I've got one problem though and that is that I can't get a view to display JUST an image - it always comes bundled with it's title and a link through to the gallery.

Can anyone help me work out how to reference an image from a view, only displaying the image itself with no linkage or anything else?

Setup

• Image installed
• Content type "recipe" created
• CCK Image field used to bring image into "recipe"
• View created - has the right image field referenced

Can select "body" or teaser on the view options for the image field, but neither is correct really. I thought about trying to re-write the output of that field, but there is no way of just passing along the file path it seems.

H

Answer 1

It sounds like you're using the node row style. If you set the row style to fields , you should be able to just display the image field.

Answer 2

Personally I use ImageCache for all image manipulations. Then you get a lot of options when you edit the Display Fields of your node type, eg

• Image display with link to node
• Image display with no link
• Thumbnail display with link to original picture
• Thumbnail display with no link

etc etc. Very useful, but it might confuse things further to have another image-based module doing things!