jQuery: Selecting elements that don't have a specific descendant element

Question

我如何使用jQuery 1.3.2选择不包含任何后代td元素的所有表元素？

Answer 1

You could try:

$("table:not(:has(tbody > tr > td))").doStuff();

Working example:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html>
<head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script>
<script type="text/javascript">
$(function() {
  $("table:not(:has(tbody > tr > td))").css("background", "yellow");
});
</script>
<style type="text/css">
table { border-collapse: collapse; }
td, th { border: 1px solid black; }
</style>
</head>
<body>
<table>
<tr>
  <td>First table</td>
</tr>
</table>
<table>
<tr>
  <th>Second table</th>
</tr>
</table>
</body>
</html>

Answer 2

You're looking for the CSS :not() selector .

table *:not(td)

Should do it.

Edit: bah, misread what you wanted.

jQuery: Selecting elements that don't have a specific descendant element

Question

2 answers

solution1
6 2009-10-21 16:50:53

solution2
1 2009-10-21 16:51:21

jQuery: Selecting elements that don't have a specific descendant element

Question

2 answers

solution1 6 2009-10-21 16:50:53

solution2 1 2009-10-21 16:51:21

solution1
6 2009-10-21 16:50:53

solution2
1 2009-10-21 16:51:21