Convert javascript to date object to mysql date format (YYYY-MM-DD)

Question

我正在尝试使用 javascript 将日期对象转换为有效的 mysql 日期 - 最好的方法是什么？

Answer 1

To get date

new Date().toJSON().slice(0, 10)
//2015-07-23

for datetime

new Date().toJSON().slice(0, 19).replace('T', ' ')
//2015-07-23 11:26:00

Note, that resulting date / datetime will always be in UTC timezone

Answer 2

Probably best to use a library like Date.js (although that hasn't been maintained in years) or Moment.js .

But to do it manually, you can use Date#getFullYear() , Date#getMonth() (it starts with 0 = January, so you probably want + 1), and Date#getDate() (day of month). Just pad out the month and day to two characters, eg:

(function() {
    Date.prototype.toYMD = Date_toYMD;
    function Date_toYMD() {
        var year, month, day;
        year = String(this.getFullYear());
        month = String(this.getMonth() + 1);
        if (month.length == 1) {
            month = "0" + month;
        }
        day = String(this.getDate());
        if (day.length == 1) {
            day = "0" + day;
        }
        return year + "-" + month + "-" + day;
    }
})();

Usage:

var dt = new Date();
var str = dt.toYMD();

Note that the function has a name, which is useful for debugging purposes, but because of the anonymous scoping function there's no pollution of the global namespace.

That uses local time; for UTC, just use the UTC versions ( getUTCFullYear , etc.).

Caveat: I just threw that out, it's completely untested.

Answer 3

This worked for me, just edit the string instead:

var myDate = new Date();
var myDate_string = myDate.toISOString();
var myDate_string = myDate_string.replace("T"," ");
var myDate_string = myDate_string.substring(0, myDate_string.length - 5);

Answer 4

The shortest version of https://stackoverflow.com/a/11453710/3777994 :

/**
 * MySQL date
 * @param {Date} [date] Optional date object
 * @returns {string}
 */
function mysqlDate(date){
    date = date || new Date();
    return date.toISOString().split('T')[0];
}

Using:

var date = mysqlDate(); //'2014-12-05'

Answer 5

function js2Sql(cDate) {
    return cDate.getFullYear()
           + '-'
           + ("0" + (cDate.getMonth()+1)).slice(-2)
           + '-'
           + ("0" + cDate.getDate()).slice(-2);
}

Answer 6

从 JS 日期到 Mysql 日期格式转换你可以简单地这样做：

date.toISOString().split("T")[0]

Answer 7

A bit of a typo in the first example, when a day has a length less than 1 it is adding the month instead of the day to the result.

Works great though if you change:

    if (day.length == 1) {
        day = "0" + month;
    }

to

    if (day.length == 1) {
        day = "0" + day;
    }

Thanks for posting that script.

The corrected function looks like:

Date.prototype.toYMD = Date_toYMD;
function Date_toYMD() {
    var year, month, day;
    year = String(this.getFullYear());
    month = String(this.getMonth() + 1);
    if (month.length == 1) {
        month = "0" + month;
    }
    day = String(this.getDate());
    if (day.length == 1) {
        day = "0" + day;
    }
    return year + "-" + month + "-" + day;
}

Answer 8

just this :

Object.defineProperties( Date.prototype ,{
    date:{
         get:function(){return this.toISOString().split('T')[0];}
    },
    time:{
         get:function(){return this.toTimeString().match(/\d{2}:\d{2}:\d{2}/)[0];}
    },
    datetime:{
         get : function(){return this.date+" "+this.time}
    }
});

now you can use

sql_query = "...." + (new Date).datetime + "....";

Answer 9

I needed this for a filename and with the time in the current timezone.

const timezoneOffset = (new Date()).getTimezoneOffset() * 60000;

const date = (new Date(Date.now() - timezoneOffset))
    .toISOString()
    .substring(0, 19)
    .replace('T', '')       // replace T with a space
    .replace(/ /g, "_")     // replace spaces with an underscore
    .replace(/\:/g, ".");   // replace colons with a dot

Source

• convert-javascript-to-date-object-to-mysql-date-format-yyyy-mm-dd
• javascript-toisostring-ignores-timezone-offset

Answer 10

// function
getDate = function(dateObj){
    var day = dateObj.getDay() < 9 ? '0'+dateObj.getDay():dateObj.getDay();
    var month = dateObj.getMonth() < 9 ? '0'+dateObj.getMonth():dateObj.getMonth();
    return dateObj.getFullYear()+'-'+month+'-'+day;
}

// example usage
console.log(getDate(new Date()));

// with custom date
console.log(getDate(new Date(2012,dateObj.getMonth()-30,dateObj.getDay()));

Answer 11

看看这个方便的库以满足您所有的日期格式需求： http : //blog.stevenlevithan.com/archives/date-time-format

Answer 12

Try this

dateTimeToMYSQL(datx) {
    var d = new Date(datx),
      month = '' + (d.getMonth() + 1),
      day = d.getDate().toString(),
      year = d.getFullYear(),
      hours = d.getHours().toString(),
      minutes = d.getMinutes().toString(),
      secs = d.getSeconds().toString();
    if (month.length < 2) month = '0' + month;
    if (day.length < 2) day = '0' + day;
    if (hours.length < 2) hours = '0' + hours;
    if (minutes.length < 2) minutes = '0' + minutes;
    if (secs.length < 2) secs = '0' + secs;
    return [year, month, day].join('-') + ' ' + [hours, minutes, secs].join(':');
  }

Note that you can remove the hours, minutes and seconds and you will have the result as YYYY-MM-DD The advantage is that the datetime entered in the HTML form remains the same: no transformation into UTC

The result will be (for your example) :

dateToMYSQL(datx) {
    var d = new Date(datx),
      month = '' + (d.getMonth() + 1),
      day = d.getDate().toString(),
      year = d.getFullYear();
    if (month.length < 2) month = '0' + month;
    if (day.length < 2) day = '0' + day;
    return [year, month, day].join('-');
  }

Answer 13

I'd like to say that this is likely the best way of going about it. Just confirmed that it works:

new Date().toISOString().replace('T', ' ').split('Z')[0];

Answer 14

Can be!

function Date_toYMD(d)
{
    var year, month, day;
    year = String(d.getFullYear());
    month = String(d.getMonth() + 1);
    if (month.length == 1) {
        month = "0" + month;
    }
    day = String(d.getDate());
    if (day.length == 1) {
        day = "0" + day;
    }
    return year + "-" + month + "-" + day;
}