Python images display Django

Question

Since my last question here: Python images display

I understood that from all the answers I got the glob.glob could be the only one in the direction I need.

However where I am stuck right now is here:

I can create a list with all the filenames in my media directory by using glob.glob:

all = glob.glob("/Path_to_MEDIA/*/*.jpg")

But how can I use that and create a VERY SIMPLE image display with one next button that calls files in my MEDIA_ROOT and displays them.

What I know is:

I have a Template which looks something like the default directory index:

 <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <meta http-equiv="Content-type" content="text/html; charset=utf-8" /> <meta http-equiv="Content-Language" content="en-us" /> <meta name="robots" content="NONE,NOARCHIVE" /> <title>Index of {{ directory }}</title> </head> <body> <h1>Index of {{ directory }}</h1> <ul> {% ifnotequal directory "/" %} <li><a href="../">../</a></li> {% endifnotequal %} {% for f in file_list %} <li><a href="{{ f|urlencode }}">{{ f }}</a></li> {% endfor %} </ul> </body> </html>

I need to create a def in my views that feeds the list from glob.glob to this or similar template.

What I dont know:

How does this def in the view have to look like?

And here:

What do I have to write to display one image, sound in a browser?
What do I have to write to display a LIST of images, sounds?

Thanks for the time!

Answer 1

Make a direct-to-template url with extra-context in urls.py:

from django.views.generic.simple import direct_to_template
...
url(r'^whatever', direct_to_template, 
                 { 'template':'foo.html', 'extra_context': {'files':myfiles} }
                 name='whatever' ),

Where myfiles above is a list/tuple of your files. However, make sure to format your file list in terms of MEDIA_URL instead of based on MEDIA_PATH. For example:

myfiles = [ 'relative/path/foo.jpg', 
            'http://static.mysite.com/absolute/path/bar.jpg' ]

Though, obviously generated from the filesystem in your case, not a hardcoded list. And you could do the work in a view rather than using direct-to-template -- just make sure to put the files key/value into your context:

def myview( request ... ):
  context = RequestContext(request)
  context[files]=myfiles
  return render_to_respone( ..., context_instance=context )

Then, in your template foo.html :

{% for file in files %}
  <img src='YOUR_MEDIA_URL_HERE/{{ file }}' />
{% endfor %}

Python images display Django

Question

1 answers

solution1
0 ACCPTED 2010-07-12 13:01:40

Python images display Django

Question

1 answers

solution1 0 ACCPTED 2010-07-12 13:01:40

solution1
0 ACCPTED 2010-07-12 13:01:40