Using an XSL for-each on identical XML children
Question
In brief, my problem is that I want to loop through the contents of one child among identical children, but when I try to do so, it loops through the contents of all the children, giving me as many duplicates of the data as there are children.
Example code:
<?xml version="1.0"?>
<base>
<item name="item1">
<foo>
<type1>1</type1>
<type2>2</type2>
</foo>
<bar>
<type3>3</type3>
</bar>
</item>
<item name="item2">
<foo>
<type1>4</type1>
<type2>5</type2>
</foo>
<bar>
<type3></type3>
<!-- NOTE! This value is missing. Therefore we must put a blank value in the table-->
</bar>
</item>
<item name="item3">
<foo>
<type1>7</type1>
<type2></type2>
<!-- NOTE! This value is missing. Therefore we must put a blank value in the table-->
</foo>
<bar>
<type3>9</type3>
</bar>
</item>
</base>
<?xml version="1.0"?>
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:cyg="http://CygNetSCADA.com/Schemas/CygNetEnterpriseObjects730">
<xsl:output method="html" encoding="UTF-8" />
<xsl:template match="/">
<html>
<body>
<table border="1">
<tr>
<th>Name</th>
<xsl:for-each select="base/item/*/*">
<th>
<xsl:value-of select="local-name()"/>
</th>
</xsl:for-each>
</tr>
<xsl:for-each select="base/item">
<tr>
<th>
<xsl:value-of select="@name"/>
</th>
<xsl:for-each select="foo/*">
<xsl:choose>
<xsl:when test=".[node()]">
<td>
<xsl:value-of select="." />
</td>
</xsl:when>
<xsl:otherwise>
<td />
<!-- This is for that empty value in item3 -->
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
<xsl:for-each select="bar/*">
<xsl:choose>
<xsl:when test=".[node()]">
<td>
<xsl:value-of select="." />
</td>
</xsl:when>
<xsl:otherwise>
<td />
<!-- This is for that empty value in item2 -->
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
What happens in this example is that the generated HTML has 10 columns - one for "name", and "type1", "type2", "type3" three times (three times for the three elements; if there were 4 elements in my input there would be 3 more columns). I only want "type1", "type2", and "type3" to display once in the column. How might I go about doing this?
All help is appreciated and thanks in advance!
1 answers
solution1
2 ACCPTED 2010-07-13 18:58:46
You're using XSL 2.0 so presumably you have access to the xsl:for-each-group element. It's what you need in this situation:
<tr>
<th>Name</th>
<xsl:for-each-group select="base/item/*/*" group-by="local-name()">
<th>
<xsl:value-of select="current-grouping-key()"/>
</th>
</xsl:for-each>
</tr>
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