MySQLi count(*) always returns 1

Question

I'm trying to count the number of rows in a table and thought that this was the correct way to do that:

$result = $db->query("SELECT COUNT(*) FROM `table`;");
$count = $result->num_rows;

But counts always returns (int)1 . If I use the same query in phpMyAdmin I get the right result. It sits in a table so I tried testing $count[0] as well, but that returns NULL .

What is the right way to do this?

Answer 1

You have to fetch that one record, it will contain the result of Count()

$result = $db->query("SELECT COUNT(*) FROM `table`");
$row = $result->fetch_row();
echo '#: ', $row[0];

Answer 2

Always try to do an associative fetch, that way you can easy get what you want in multiple case result

Here's an example

$result = $mysqli->query("SELECT COUNT(*) AS cityCount FROM myCity")
$row = $result->fetch_assoc();
echo $row['cityCount']." rows in table myCity.";

Answer 3

I find this way more readable:

$result = $mysqli->query('select count(*) as `c` from `table`');
$count = $result->fetch_object()->c;
echo "there are {$count} rows in the table";

Not that I have anything against arrays...

Answer 4

This worked well for me.

        // Veh Pro Count
    $query_tvp = "SELECT count(*) as total from submit";
    if ($result_tvp = $mysqli->query("$query_tvp")) {
        /* determine number of rows result set */
        $total_tvp = $result_tvp->fetch_row();
        $total_tvp = $total_tvp['0'];
        /* close result set */
        $result_tvp->close();
    }

            echo "Total: $total_tvp";

Answer 5

its very sample.

$query="select count(*)as count from users";
$result=$connection->query($query);
$count=mysqli_fetch_assoc($result)["count"];
echo $count;

Answer 6

$result->num_rows; only returns the number of row(s) affected by a query. When you are performing a count(*) on a table it only returns one row so you can not have an other result than 1.

Answer 7

For me this works, this is when you want to count a repeated elements inside a register.

For example: number of people who mark 'yes' in a form.

table: users

register: vote

element of register: yes / no

$sql_user = "SELECT COUNT(*) FROM users WHERE vote = 'yes'";    
$result1 = $mysqli->query($sql_user);    
$row1 = $result1->fetch_row();    
$n_yes = $row1['0'];