PHP 404 response header
Question
I use .htaccess RewriteRules to pass the url to index.php. If the specified page name isn't found in the database, I want my script to throw proper 404 responses.
The way I have tried to achieve this is:
header($_SERVER["SERVER_PROTOCOL"] . " 404 Not Found");
Analysing the HTTP responses in my browser, the response comes back fine:
HTTP/1.1 404 Not Found
However, I would like to be able to output a friendly 404 page, but anything after the header() function gets disregarded, and anything before ... well ... that'd be stupid.
Can anyone suggest how to output a 404 error message from the script?
Thanks.
3 answers
solution1
3 ACCPTED 2010-09-11 13:26:53
You have to make sure the output (or ErrorDocument) is larger than 512 bytes as to make sure Internet Explorer doesn't display it's own error-page. This is probably why you have experienced any output after the header doesn't get displayed.
solution2
1 2010-09-11 13:24:21
<?php
header("HTTP/1.0 404 Not Found");
echo "<!DOCTYPE HTML PUBLIC \"-//IETF//DTD HTML 2.0//EN\">
<html><head>
<title>404 Not Found</title>
</head><body>
<h1>Not Found</h1>
<p>The requested URL " . $_SERVER['REQUEST_URI'] . " was not found on this server.</p>
<hr>
<address>Apache/2.2.3 (CentOS) Server at " . $_SERVER['SERVER_NAME'] . " Port 80</address>
</body></html>";
exit();
?>
solution3
0 2010-09-11 13:20:02
So following (in .htaccess)
ErrorDocument 404 /errordoc.html
is not working for you ?
EDIT: As you see, you can easy throw 404 in PHP and then catch it in .htaccess.
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.