What is this assignment construct called? And can you do it in Php?

Question

I have often used the following construct in Javascript:

var foo = other_var || "default_value";

In Javascript, if the left side is falsy, then the value on the right side is assigned.

It is very handy, and saves writing longer and unnecessarily explicit ternary expressions.

Is there a name for this sort of construct ?

Bonus: Is there a trick to do this in Php without using a ternary operator?

PS: another variant is to throw an error if you don't get a truthy value, instead of giving a default value:

var foo = something || alert("foo is not set!");

Answer 1

The logical-or (usually || ) operator is drastically different in many languages.

In some (like C, C++ ) it works like: "Evaluate the left-hand side; if it's true, return true, otherwise evaluate the right hand-side and return true if it's true or false otherwise." The result is always boolean here.

In others (like Javascript, Python , I believe that PHP also) it's more like: "Evaluate the left-hand side; if it's true, return it, otherwise evaluate the right-hand side and return the result." Then the result can be of any type and you can do constructs like:

a = (b || c); // equivalent to a = b ? b : c;

or quite fancy:

function compare(A, B) { // -1 if A<B, 0 if A==B, 1 if A>B
    return B.x - A.x || B.y - A.y;
}

Answer 2

I believe it's just called an OR construct. There are a lot of good examples on using assignments here: http://php.net/manual/en/language.operators.assignment.php

Answer 3

It is just a logical OR operator . Follow the link for more information in javascript.

From the examples in the docs:

o1=true || true       // t || t returns true
o2=false || true      // f || t returns true
o3=true || false      // t || f returns true
o4=false || (3 == 4)  // f || f returns false
o5="Cat" || "Dog"     // t || t returns Cat
o6=false || "Cat"     // f || t returns Cat
o7="Cat" || false     // t || f returns Cat

---

EDIT: Regarding the BONUS, it appears as though you can do something similar with the ternary in recent versions of PHP by doing:

expr1 ?: expr3

From the PHP docs:

Since PHP 5.3, it is possible to leave out the middle part of the ternary operator. Expression expr1 ?: expr3 returns expr1 if expr1 evaluates to TRUE , and expr3 otherwise.

I'm not familiar with PHP, so I'd be interested to know the result.

Answer 4

This works:

$mytruevalue = true;
$foo = $mytruevalue or $foo = "20";
echo $foo;

The above prints "1" because that is the string representation of true ( $mytruevalue is true).

$myfalsevalue = false;
$foo = $myfalsevalue or $foo = "20";
echo $foo;

This, however, prints "20" because $myfalsevalue is false.

If both values are equal to false , it prints nothing.

Hope this helps.

Answer 5

Is there a name for this sort of construct ?

It is the logical OR operator .

Bonus: Is there a trick to do this in Php without using a ternary operator?

No, with PHP, you can do so only with the help of ternay operator.