Should I use encodeURI or encodeURIComponent for encoding URLs?

Question

应该使用这两种方法中的哪一种来编码 URL？

Answer 1

It depends on what you are actually wanting to do.

encodeURI assumes that the input is a complete URI that might have some characters which need encoding in it.

encodeURIComponent will encode everything with special meaning, so you use it for components of URIs such as

var world = "A string with symbols & characters that have special meaning?";
var uri = 'http://example.com/foo?hello=' + encodeURIComponent(world);

Answer 2

If you're encoding a string to put in a URL component (a querystring parameter), you should call encodeURIComponent .

If you're encoding an existing URL, call encodeURI .

Answer 3

xkr.us has a great discussion, with examples. To quote their summary:

The escape() method does not encode the + character which is interpreted as a space on the server side as well as generated by forms with spaces in their fields. Due to this shortcoming and the fact that this function fails to handle non-ASCII characters correctly, you should avoid use of escape() whenever possible. The best alternative is usually encodeURIComponent().

escape() will not encode: @*/+

Use of the encodeURI() method is a bit more specialized than escape() in that it encodes for URIs as opposed to the querystring, which is part of a URL. Use this method when you need to encode a string to be used for any resource that uses URIs and needs certain characters to remain un-encoded. Note that this method does not encode the ' character, as it is a valid character within URIs.

encodeURI() will not encode: ~!@#$&*()=:/,;?+'

Lastly, the encodeURIComponent() method should be used in most cases when encoding a single component of a URI. This method will encode certain chars that would normally be recognized as special chars for URIs so that many components may be included. Note that this method does not encode the ' character, as it is a valid character within URIs.

encodeURIComponent() will not encode: ~!*()'

Answer 4

Here is a summary.

1. escape() will not encode @ * _ + - . /

   Do not use it.

2. encodeURI() will not encode AZ az 0-9 ; , / ? : @ & = + $ - _ . ! ~ * ' ( ) #

   Use it when your input is a complete URL like ' https://searchexample.com/search?q=wiki '

3. encodeURIComponent() will not encode AZ az 0-9 - _ . ! ~ * ' ( ) Use it when your input is part of a complete URL eg const queryStr = encodeURIComponent(someString)

Answer 5

encodeURI and encodeURIComponent are used for different purposes.
Some of the difference are

1. encodeURI is used to encode a full URL whereas encodeURIComponent is used for encoding a URI component such as a query string.

2. There are 11 characters which are not encoded by encodeURI, but encoded by encodeURIComponent. List:

Character	encodeURI	encodeURIComponent
#	#	%23
$	$	%24
&	&	%26
+	+	%2B
,	,	%2C
/	/	%2F
:	:	%3A
;	;	%3B
=	=	%3D
?	?	%3F
@	@	%40

Notes:
encodeURIComponent does not encode -_.!~*'(). If you want to these characters are encoded, you have to replace them with a corresponding UTF-8 sequence of characters

If you want to learn more about encodeURI and encodeURIComponent, please check the reference link. Reference Link

Answer 6

encodeURIComponent() : assumes that its argument is a portion (such as the protocol, hostname, path, or query string) of a URI. Therefore it escapes the punctuation characters that are used to separate the portionsof a URI.

encodeURI(): is used for encoding existing url

Answer 7

Difference between encodeURI and encodeURIComponent :

encodeURIComponent(value) is mainly used to encode queryString parameter values, and it encodes every applicable character in value . encodeURI ignores protocol prefix ( http:// ) and domain name.

---

In very, very rare cases, when you want to implement manual encoding to encode additional characters (though they don't need to be encoded in typical cases) like: ! * ! * , then you might use:

function fixedEncodeURIComponent(str) {
  return encodeURIComponent(str).replace(/[!*]/g, function(c) {
    return '%' + c.charCodeAt(0).toString(16);
  });
}

( source )

Answer 8

Other answers describe the purposes. Here are the characters each function will actually convert :

control = '\x00\x01\x02\x03\x04\x05\x06\x07\x08\x09\x0A\x0B\x0C\x0D\x0E\x0F'
        + '\x10\x11\x12\x13\x14\X15\x16\x17\x18\x19\x1A\x1B\x1C\x1D\x1E\x1F'
                                                                    + '\x7F'
encodeURI         (control + ' "%<>[\\]^`{|}'                             )
encodeURIComponent(control + ' "%<>[\\]^`{|}' + '#$&,:;=?' + '+/@'        )
escape            (control + ' "%<>[\\]^`{|}' + '#$&,:;=?' +       "!'()~")

All characters above are converted to percent-hexadecimal codes. Space to %20 , percent to %25 , etc. The characters below pass through unchanged.

Here are the characters the functions will NOT convert :

pass_thru = '*-._0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz'

encodeURI         (pass_thru + '#$&,:;=?' + '+/@' + "!'()~")
encodeURIComponent(pass_thru +                      "!'()~")
escape            (pass_thru +              '+/@'          )

Answer 9

As a general rule use encodeURIComponent . Don't be scared of the long name thinking it's more specific in it's use, to me it's the more commonly used method. Also don't be suckered into using encodeURI because you tested it and it appears to be encoding properly, it's probably not what you meant to use and even though your simple test using "Fred" in a first name field worked, you'll find later when you use more advanced text like adding an ampersand or a hashtag it will fail. You can look at the other answers for the reasons why this is.