Ext Js: make button a link

Question

In Ext Js I want some of my buttons to work like links (ie <a href... ).

How can I do that.

Right now I am adding a handler that does window.location.href=http://.... .

But I thought there should be an easier way - something like adding an href attribute like in menu item.

Some ideas?

Answer 1

That's the way it's done... To be more portable you could extend Ext.Button into Ext.ux.LinkButton (or whatever) and implement the property and the required behavior in this extended class (just a quick-&-dirty example):

Ext.ux.LinkButton = Ext.extend(Ext.Button, {
    href: null,
    handler: function() {
        if (this.href) {
            window.location.href = this.href;
        }
    } 
}); 
Ext.reg( "ux-linkbutton", Ext.ux.LinkButton );

var btn = new Ext.ux.LinkButton({
    text: "Link to Google",
    href: "http://www.google.com"
});

EDIT:

Simple change of appearance:

Ext.ux.LinkButton = Ext.extend(Ext.Button, {
    href: null,
    template: new Ext.Template(
        ['<table id="{4}" cellspacing="0" class="x-btn {3}"><tbody class="{1}">',
        '<tr><td class="x-btn-tl"><i>&#160;</i></td><td class="x-btn-tc"></td><td class="x-btn-tr"><i>&#160;</i></td></tr>',
        '<tr><td class="x-btn-ml"><i>&#160;</i></td><td class="x-btn-mc"><em class="{2}" unselectable="on"><a href="{0}"></a></em></td><td class="x-btn-mr"><i>&#160;</i></td></tr>',
        '<tr><td class="x-btn-bl"><i>&#160;</i></td><td class="x-btn-bc"></td><td class="x-btn-br"><i>&#160;</i></td></tr>',
        '</tbody></table>'], {compiled: true}),
    buttonSelector : 'a:first-child',
    getTemplateArgs : function(){
        return [this.href, 'x-btn-' + this.scale + ' x-btn-icon-' + this.scale + '-' + this.iconAlign, this.getMenuClass(), this.cls, this.id];
    },
    handler: function(b, e) {
        if (this.href) {
            e.stopEvent();
            window.location.href = this.href;
        }
    } 
}); 

Answer 2

还有一个现有的用户扩展 ，它正是这样做的。