I thought this was going to be straight forward but I managed to hose it up some how. If I want to pass URL parameters to another action do I have to create a new route for that?
controller
[ChildActionOnly]
public ActionResult ContentSection(string sectionAlias, string mvcController, string mvcAction = null)
view
@Html.RenderAction("ContentSection", "Portal", new {sectionAlias = "TermsAndConditions", mvcController = "Portal", mvcAction = "ChoosePayment"})
error
CS1502: The best overloaded method match for 'System.Web.WebPages.WebPageExecutingBase.Write(System.Web.WebPages.HelperResult)' has some invalid arguments
The problem here is that
@Html.RenderAction("ContentSection", "Portal", new {sectionAlias = "TermsAndConditions", mvcController = "Portal", mvcAction = "ChoosePayment"})
Is the equivalent to
<%= Html.RenderAction("ContentSection", "Portal", new {sectionAlias = "TermsAndConditions", mvcController = "Portal", mvcAction = "ChoosePayment"}) %>
In the the Webforms ViewEngine
(which is also the same a Response.Write
). Since RenderAction
returns void
, you cannot Response.Write
it. What you want to do is this:
@{
Html.RenderAction("ContentSection", "Portal", new {sectionAlias = "TermsAndConditions", mvcController = "Portal", mvcAction = "ChoosePayment"});
}
The @{ }
syntax signifies a code block in the Razor view engine, which would be equivalent to the following the the Webforms ViewEngine
:
<% Html.RenderAction("ContentSection", "Portal", new {sectionAlias = "TermsAndConditions", mvcController = "Portal", mvcAction = "ChoosePayment"}); %>
The short answer would be: use @Html.Action().
@Html.Action("ContentSection", "Portal", new {sectionAlias = "Terms", ...})
The long answer was already given by Nathan Anderson.
PS Credit for this answer really goes to James Nail, who posted it as a comment in Nathan's answer, but I found it so easy and valuable that I thought it should be an individual answer.
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