Get Color Shade with PHP

Question

I want to get brighter hex colour shade output from a given hex value with PHP. For example, I give the colour #cc6699 as input, and I want #ee88aa as the output colour. How would I go about doing this in PHP?

Answer 1

You need to convert the color to RGB, make the additions, and convert back:

// Convert string to 3 decimal values (0-255)
$rgb = array_map('hexdec', str_split("cc6699", 2));

// Modify color
$rgb[0] += 34;
$rgb[1] += 34;
$rgb[2] += 17;

// Convert back
$result = implode('', array_map('dechex', $rgb));

echo $result;

See it in action here .

Answer 2

1.将颜色分为三个元素：cc，66、99 2.使用http://php.net/manual/de/function.hexdec.php将其转换为十进制3.递增三个十进制值4.将十进制转换为十六进制再次5.将三个要素放在一起

Answer 3

与您的问题没有直接关系，但是这篇文章对颜色转换很有趣： http : //beesbuzz.biz/code/hsv_color_transforms.php

Answer 4

The best solution is to convert the RGB to HSL or HSV (just search google for php converter hsl/hsv ).

Then you can play with the 'lightness' or 'value' values of the colorspace.

Afterwards convert it back to RGB colorspace.