I have a Python list of dictionary in the form eg
[{'Parent':'top', 'Child':'obj1', 'Level':0},
{'Parent':'obj1', 'Child':'obj2', 'Level':1},
{'Parent':'obj1', 'Child':'obj3', 'Level':1},
{'Parent':'obj2', 'Child':'obj4', 'Level':2},
{'Parent':'obj4', 'Child':'obj5', 'Level':3}]
I want to write this out as a nested html list based on the Parent eg
How can I do this in a Django template
Quick solution:
def make_list(d):
def append_children(parent, d):
children = [[x['Child']] for x in d if x['Parent'] == parent[0]]
if children:
parent.append(children)
for child in children:
append_children(child, d)
results = [[x['Child']] for x in d if x['Parent'] == 'top']
for parent in results:
append_children(parent, d)
return results
Pass the list into this function and then apply unordered_list
filter to the result. The disadvantage of this method is that <ul>
list is created even for one element ( <ul><li>elem</li></ul>
), but you can alter display as you like with CSS.
If you want clearer HTML you should write a custom tag or filter for that.
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.