Here is my problem
I want to move a div from its position to the mouses position when i mouseover an element.
Almost like a "tooltip", but when i mouseover it doesnt move. Here is the code:
$item.mouseover(function (){
//make visible
$tooltip.show();
//change left and top values to mouse values
$tooltip.css("left","event.clientX + 'px'");
$tooltip.css("top","200px");
});
The "event.clientX + 'px'" doesn't seem to work, is there anyway i can get this to work? The top attribute is changed without problems but I cant get the mouse value to work.
how can i change the item.left & .top values to that of the mouses?
ty in advance!
-Thaiscorpion
edit: Wow thats for the really super fast answers im gonna trythem right now thanx!!
You're setting the css property to event.clientXpx
literally. Put event.clientX
outside the quotes:
$tooltip.css("left", event.clientX + "px");
Here is a redone version of your code: http://jsfiddle.net/maniator/EzdBx/
var $tooltip = $('#tooltip')
$('.hover').hover(function(event) {
//make visible
$tooltip.show();
//change left and top values to mouse values
$(this).bind('mousemove', function(event) {
$tooltip.css("left", event.clientX);
$tooltip.css("top", event.clientY);
})
}, function() {
$tooltip.hide();
});
css:
#tooltip {
display: none;
position: absolute;
/* anything you want here and below */
width: 50px;
background: blue;
}
replace:
$item.mouseover(function (){
//make visible
$tooltip.show();
//change left and top values to mouse values
$tooltip.css("left","event.clientX + 'px'");
$tooltip.css("top","200px");
});
with:
$item.mouseover(function (){
//make visible
$tooltip.show();
//change left and top values to mouse values
$tooltip.css("left",event.clientX + 'px');
$tooltip.css("top","200px");
});
You're treating the event object as a string. So your call to $.css()
would be more like this:
$item.mouseenter(function(event){
$tooltip
.show()
.css({
left: event.clientX + "px",
top: '200px'
});
});
您需要更改其position
属性,可能还要更改z-index
。
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