Make an image follow mouse pointer
Question
I need a rocket to follow the movements of the mouse pointer on my website. This means it should rotate to face the direction of motion, and if possible, accelerate depending on the distance it has to cover. Is this even possible ? jquery perhaps ?
3 answers
solution1
34 ACCPTED 2011-08-22 06:34:47
by using jquery to register .mousemove to document to change the image .css left and top to event.pageX and event.pageY.
example as below http://jsfiddle.net/BfLAh/1/
$(document).mousemove(function(e) { $("#follow").css({ left: e.pageX, top: e.pageY }); });
#follow { position: absolute; text-align: center; }
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script> <div id="follow"><img src="https://placekitten.com/96/140" /><br>Kitteh</br> </div>
updated to follow slowly
for the orientation , you need to get the current css left and css top and compare with event.pageX and event.pageY , then set the image orientation with
-webkit-transform: rotate(-90deg);
-moz-transform: rotate(-90deg);
for the speed , you can set the jquery .animation duration to certain amount.
solution2
12 2011-08-22 06:54:05
Ok, here's a simple box that follows the cursor
Doing the rest is a simple case of remembering the last cursor position and applying a formula to get the box to move other than exactly where the cursor is. A timeout would also be handy if the box has a limited acceleration and must catch up to the cursor after it stops moving. Replacing the box with an image is simple CSS (which can replace most of the setup code for the box). I think the actual thinking code in the example is about 8 lines.
Select the right image (use a sprite) to orientate the rocket.
Yeah, annoying as hell. :-)
function getMouseCoords(e) { var e = e || window.event; document.getElementById('container').innerHTML = e.clientX + ', ' + e.clientY + '<br>' + e.screenX + ', ' + e.screenY; } var followCursor = (function() { var s = document.createElement('div'); s.style.position = 'absolute'; s.style.margin = '0'; s.style.padding = '5px'; s.style.border = '1px solid red'; s.textContent = "🚀" return { init: function() { document.body.appendChild(s); }, run: function(e) { var e = e || window.event; s.style.left = (e.clientX - 5) + 'px'; s.style.top = (e.clientY - 5) + 'px'; getMouseCoords(e); } }; }()); window.onload = function() { followCursor.init(); document.body.onmousemove = followCursor.run; }
#container { width: 1000px; height: 1000px; border: 1px solid blue; }
<div id="container"></div>
solution3
6 2013-10-03 16:01:10
Here's my code (not optimized but a full working example):
<head> <style> #divtoshow {position:absolute;display:none;color:white;background-color:black} #onme {width:150px;height:80px;background-color:yellow;cursor:pointer} </style> <script type="text/javascript"> var divName = 'divtoshow'; // div that is to follow the mouse (must be position:absolute) var offX = 15; // X offset from mouse position var offY = 15; // Y offset from mouse position function mouseX(evt) {if (!evt) evt = window.event; if (evt.pageX) return evt.pageX; else if (evt.clientX)return evt.clientX + (document.documentElement.scrollLeft ? document.documentElement.scrollLeft : document.body.scrollLeft); else return 0;} function mouseY(evt) {if (!evt) evt = window.event; if (evt.pageY) return evt.pageY; else if (evt.clientY)return evt.clientY + (document.documentElement.scrollTop ? document.documentElement.scrollTop : document.body.scrollTop); else return 0;} function follow(evt) { var obj = document.getElementById(divName).style; obj.left = (parseInt(mouseX(evt))+offX) + 'px'; obj.top = (parseInt(mouseY(evt))+offY) + 'px'; } document.onmousemove = follow; </script> </head> <body> <div id="divtoshow">test</div> <br><br> <div id='onme' onMouseover='document.getElementById(divName).style.display="block"' onMouseout='document.getElementById(divName).style.display="none"'>Mouse over this</div> </body>
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.