jQuery DatePicker with today as maxDate

Question

我想将今天的日期设置为 jQuery datepicker 的 maxdate 以防止用户选择大于今天的日期

Answer 1

$(".datepicker").datepicker({maxDate: '0'});

This will set the maxDate to +0 days from the current date (ie today). See:

http://api.jqueryui.com/datepicker/#option-maxDate

Answer 2

http://api.jqueryui.com/datepicker/#option-maxDate

$( ".selector" ).datepicker( "option", "maxDate", '+0m +0w' );

Answer 3

如果您使用的是 bootstrap 3 日期时间选择器，请尝试以下操作：

$('.selector').datetimepicker({ maxDate: $.now() });

Answer 4

In recent version, The following works fine:

    $('.selector').datetimepicker({
        maxDate: new Date()
    });

maxDate accepts a Date object as parameter.

The following found in documentation:

Multiple types supported:

• Date: A date object containing the minimum date.

• Number: A number of days from today. For example 2 represents two days from today and -1 represents yesterday.

• String: A string in the format defined by the dateFormat option, or a relative date. Relative dates must contain value and period pairs; valid periods are "y" for years, "m" for months, "w" for weeks, and "d" for days. For example, "+1m +7d" represents one month and seven days from today.

Answer 5

For those who dont want to use datepicker method

var alldatepicker=  $("[class$=hasDatepicker]");

alldatepicker.each(function(){

var value=$(this).val();

var today = new Date();

var dd = today.getDate();

var mm = today.getMonth()+1; //January is 0!

var yyyy = today.getFullYear();

if(dd<10) {

    dd='0'+dd

} 
if(mm<10) {

    mm='0'+mm

} 
today = mm+'/'+dd+'/'+yyyy;
if(value!=''){
if(value>today){
alert("Date cannot be greater than current date");
}
}
});