I want to pass a URL from javascript to a django view. I have the following urls.py
--- urls.py ---
url(r'^show/(?P<url>\.+)$', 'myapp.views.jsonProcess'),
The view has the following declaration:
--- views.py ---
def jsonProcess(request, url):
The URL I pass in javascript is as follows:
url = 'http://127.0.0.1:8000/show/' + 'http://www.google.com';
window.open(url);
I get a "Page not Found (404)" error while matching the URL. What am I missing? Any, and all pointers are welcome since I am hopelessly stuck! :(
Firstly, you don't need to escape the dot if you want it to mean any symbol (in urls.py
).
url(r'^show/(?P<url>.+)$', 'myapp.views.json_process')
Secondly, use encodeURIComponent
to properly escape the parameter.
var url = 'http://127.0.0.1:8000/show/' +
encodeURIComponent('http://www.google.com')
By the way, don't use mixedCase for function names in Python:
Function names should be lowercase, with words separated by underscores as necessary to improve readability.
Another note that might help in future: don't hardcode Django URLs in JavaScript. You can generate them dynamically either in your views :
from django.core.urlresolvers import reverse
url = reverse(
'myapp.views.json_process',
kwargs={'url': 'http://www.google.com'}
)
Or in templates :
{% url myapp.views.json_process url="http://www.google.com" %}
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