how to change the background images with fade
Question
I have the code below,and I want to images to be change with a fade,the images now are been replaced by the function 'changeBg',but they are just been replaced without fade.
how can I "merge" between the function that's changing the images and the function that in charge of the fade.
thanks.
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<meta http-equiv="X-UA-Compatible" content="IE=7">
<title>none</title>
<link rel="stylesheet" type="text/css" href="Css/design.css" >
<script src="query-1.4.4.js" type="text/javascript"></script>
<script type="text/javascript">
$(document).ready(function()
{
$(document).ready(function() ({$('').fadeIn(1000);
});
</script>
<script language="JavaScript">
function changeBg (color) {
document.getElementById("wrapper").style.background="url(Images/"+color+".jpg) no-repeat";}
</script>
</head>
<body>
<div id="wrapper" class="wrapper">
<div class="logo"><a href="http://mazonit.co.il/"><img border="0" src="Images/logo.png" ></a>
</div>
<div class="menu">
<a href="#" id="arrowleft"><img border="0" src="Images/arrowleft.png" ></a>
<img border="0" src="Images/black.png" onclick="changeBg(this.name);" name="black">
<img border="0" src="Images/blue.png" onclick="changeBg(this.name);" name="blue">
<img border="0" src="Images/fuksia.png" onclick="changeBg(this.name);" name="fuksia">
<img border="0" src="Images/brown.png" onclick="changeBg(this.name);" name="brown">
<img border="0" src="Images/orange.png" onclick="changeBg(this.name);" name="orange">
<img border="0" src="Images/red.png" onclick="changeBg(this.name);" name="red">
<img border="0" src="Images/grey.png" onclick="changeBg(this.name);" name="grey">
<img border="0" src="Images/white.png" onclick="changeBg(this.name);" name="white">
<a href="#" id="arrowright"><img border="0" src="Images/arrowright.png" ></a>
</div>
</body>
</html>
Thanks!
2 answers
solution1
0 2011-11-14 23:44:18
If I understand you correctly, you might be able to fade the background out, change it, then fade it back in again? Like this:
function changeBg (color) {
$('#wrapper').fadeOut(1000,function(){
$(this).css('background','url(Images/'+color+'.jpg) no-repeat').fadeIn(1000);
});
}
solution2
0 2011-11-15 00:02:55
The cross-fading (fade out while fading in) is achieved in jQuery by having the statements straigh in line and not inside functions from previos animation.
Also, I understand that you want JUST THE BACKGROUND IMAGE to fadeout and fadein; not the actual contents of the page.
To achieve that, make your background image a separate item altogether but inside of the main div you have backgrounded:
<div id='wrapper' style='position:relative' > <!-- must be relative -->
<img id='bg1' src='initial.image' style='position:absolute; top:0; left:0;
width:100%; height:100%; opacity:0.2; display:none; ' />
<img id='bg2' src='initial.imageTWO' style='position:absolute; top:0; left:0;
width:100%; height:100%; opacity:0.2; display:none; ' />
</div>
function changeBackground(which) {
$('#bg'+which).attr('src','current-image.xxx').fadeOut('slow');
which = (which = 1) ? 2 : 1;
$('#bg'+which).attr('src','next-image.xxx').fadeIn('slow');
setTimeout('changeBackground('+which+')',2000);
}
$(document).ready( function () {
$('#bg1').attr('src','image-name.xxx').fadeIn('slow');
setTimeout('changeBackground(1)',2000); //every 2 seconds?
. ......
});
In case you have various images for the "slide show", you might want to add a random
number generation for which picture to show next.
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