warning: comparison between pointer and integer [enabled by default] in c

Question

I want to check whether the user input contains only digits or not. So, I use the following code:

for(i = 0; argv[1][i] != NULL; i++)
    if(!isdigit(argv[1][i]))
    {
        printf("Error");
        return -1;
    }

It works well but I got this warning:

warning: comparison between pointer and integer [enabled by default]

since argv[1][i] is an Integer and NULL is a pointer. How can I avoid such warning?

Answer 1

NULL is not the same as the null-terminator character. You should use '\\0' instead.

Answer 2

argv [1] [i]是一个字符，只需将它与'\\ 0'或0进行比较，它就更清楚了。

Answer 3

对于字符比较，可以使用（或者只使用0）;

for(i = 0; argv[1][i] != '\0'; i++)