How do I obtain the current url without params in Yii?

Question

I am using Yii.
if my url is http://localhost/evengee/event/page/id/2/sfn+master/?tab=3 My real url (file path) is only http://localhost/evengee
How would I obtain, preferably in the view:

1. full url http://localhost/evengee/event/page/id/2/sfn+master/?tab=3
2. url without explicit parameters http://localhost/evengee/event/page/id/2/sfn+master/

I know I can split/explode str_replace by the ? and use $_SERVER. Would prefer to use Yii native methods.

Answer 1

For:

• full URL ( http://localhost/even/page/id/2/?t=3 ) use Yii::app()->request->getUrl() ,

• URL without parameters ( http://localhost/even/page/id/2/ use Yii::app()->request->getPathInfo() .

Second one will give you the URL without schema, server and query string. This seems good enough.

Answer 2

To get the full URL, use the getRequestUrl() method of CHttpRequest Yii::app()->request->getRequestUrl();

You can get the controller, module and action name of the current page from the CApplication methods Yii::app()->getController()->id; //gets you the controller id Yii::app()->getController()->id; //gets you the controller id

Yii::app()->getController()->getAction()->id; //gets you the action id

You can piece together a URL using the baseURL property of CApplication

Yii::app()->baseURL

Answer 3

The best and shorter way I found is:

Yii::app()->createAbsoluteUrl(Yii::app()->request->getPathInfo());

OR

$this->createAbsoluteUrl(Yii::app()->request->getPathInfo());

Answer 4

For Yii2, use \\yii\\helpers\\Url::canonical() .

Documentation: https://www.yiiframework.com/doc/api/2.0/yii-helpers-baseurl#canonical()-detail