1 to 1..0 relationship in an embedded form with doctrine

Question

One user may have just 1 item or none. (1-1..0 relationship)

I'm trying to accomplish that in symfony2 with doctrine.

I've accomplished an 1 to 1 relationship, it's fairly simple. But how can I specify to doctrine that when I want to create an user, the item can be null? (and not to insert a new row and just leave id_item null)

This is what I have:

// User Class
     /**
     * 
     * @ORM\OneToOne(targetEntity="Items", cascade={"persist"})
     * @ORM\JoinColumn(name="id_item", referencedColumnName="id", nullable=true)
     * 
     * @var SOA\AXBundle\Entity\Items $userItem
     * @Assert\Type(type="SOA\AXBundle\Entity\Items")
     */ 
    protected $userItem;

And of course, I created ItemsTypeForm class, and added the type in my userstypeform class:

// UsersTypeForm Class
     ->add('userItem', new \SOA\AXBundle\Form\ItemsTypeForm())

When I add a new user, everything goes fine. The user is inserted as well as the item. But when I try to add an user where it has no item ( user item fields are blank ), I get the following error:

SQLSTATE[23000]: Integrity constraint violation: 1048 Column 'name' cannot be null

It is trying to insert the item, with null values.

While I can live with an 1 to 1 relationship, I would like to learn how to make an 1 to 1..0 relationship.

edited with the real problem. edits are bold.

Answer 1

The annotation of the Assert is causing a problem. You must set that the null value is valid in the Assert.