How can I fire jQuery outside document.ready block?
Question
The common method of starting jQuery is putting it in
$(document).ready(function() {
// put all jQuery stuff here
});
But what if I have a complicated site which uses basic jQuery in <head> and some custom functions that depend on the page type (eg if I have login page, fire some login ajax stuff).
So, how can I attach code to $(document).ready() or fire it later? Which JS syntax should I use?
Thanks for help!
My page structire is similar to this:
- Display static header using PHP's
include() - Add content inside
<body></body> - Display the template footer
<?php
include_once('system/classes/class.display.php');
$d = new IFDisplay();
$d->display_header(array('subtitle' => 'Log In')); <-- Here it displays static
head tags. There is
document.ready in there.
I can't change it.
?>
<script type="text/javascript">
AND WHAT DO I NEED TO PUT HERE
</script>
<div>...</div>
<?php
$d->display_footer();
?>
2 answers
solution1
4 ACCPTED 2012-02-03 19:22:26
If you aren't worried about race conditions, you should be able to use this:
$(function(){
//put your code here
});
As many times as you like.
solution2
2 2012-02-03 19:25:53
If you have a block of code that you want to be able to run BOTH in a $(document).ready() function and sometime later like when an ajax call completes, then you can just define a function and call it both places like this:
// define this in the global scope or some other publicly available scope (not inside a document.ready() call).
function myOperation() {
// put your code here
}
$(document.ready(function() {
myOperation();
});
And, then sometime later (like in an ajax call in your other code), you can call that same function with this:
myOperation()
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