In my website i have an image that when hover it goes up using this.
HTML
<div class="first">
<a href="#dialogdemo" name="modal"><img src="images/1sticon.png" alt=" " border="0"/></a>
<div class="support">
<img src="images/orpan.png" alt=" " />
</div>
</div>
Jquery
$('.first img').hover(
function(){
$(this).stop().animate({marginTop:'-25px',}, 300);
},
function(){
$(this).stop().animate({marginTop:'0px',}, 300);
}
);
but i have another image at the back of it that when hover i want the image above it to stay on its place and when mouseout it the 1st image above will go down to cover the image under it (back image).
I dont understand fully what your requirement is but I think you can use .live() of jquery to achieve what you want
$('.support1 img').live('mouseenter',function(){
"your code"
}).live('mouseleave',function(){
"your code"
});
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