Why is is top:50% in css not working?

Question

I am making a website and I'm trying to vertically center:

 position: absolute;
 width:1200px;
 height:600px;
 top: 50%;
 left: 50%;
 margin-left: -600px;

and my HTML is a single div

Answer 1

I think this should be helpful :)

 i{ -webkit-transform: translate(-50%,-50%); transform: translate(-50%,-50%); position: absolute; top: 50%; left: 50%; } 

 <i>center</i> 

Answer 2

To answer your question why top: 50% is not working, when you use property top on an element, the parent of that element needs to have a static height set in place. This should be in px or a unit other than percent. If you really need to use percent in your parent as well, then you can move on to the next parent (which is the parent of that parent) and have that one a fixed static height.

To vertically centering anything. I prefer to use this method

The use of CSS transform since you don't have to know what the width of height your element has.

position: relative;
top: 50%;
left: 50%;
-webkit-transform: translate(-50%, -50%);
-moz-transform: translate(-50%, -50%);
-ms-transform: translate(-50%, -50%);
-o-transform: translate(-50%, -50%);
transform: translate(-50%, -50%);

Don't forget to add browser/vendor prefixes.

You can refer here for vendor prefixes.

---

If you don't know the height of your parent. You have two options:

1. Using JavaScript take the natural height of the parent element and then set the height property of that parent element to the value you just took. You can use this method when the height of the parent element is caused by another child element that is sibling to the element you are centering.

 $('.parent').height( $(this).height() ); 

 .parent { /* Unkown height */ } .child { /* Create columns */ width: 50%; float: left; } .child-1 { position: relative; top: 50%; text-align: center; -webkit-transform: translateY(-50%); -moz-transform: translateY(-50%); -ms-transform: translateY(-50%); -o-transform: translateY(-50%); transform: translateY(-50%); } 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <!-- Example Start --> <div class="parent"> <div class="child child-1"> Lorem ipsum </div> <div class="child child-2"> Lorem ipsum dolor sit amet, consectetur adipiscing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua. Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo consequat. Duis aute irure dolor in reprehenderit in voluptate velit esse cillum dolore eu fugiat nulla pariatur. Excepteur sint occaecat cupidatat non proident, sunt in culpa qui officia deserunt mollit anim id est laborum. </div> </div> 

Tip: If you are taking responsive into concern, just set height again in JavaScript on browser resize. You can get the new natural height by setting height to auto in JavaScript and do the process again.

2. You can scratch the ideas above and use centering with display: table instead. CSS-Tricks has a very good example here .

Answer 3

The CSS property top works exactly as left . It pushes the div from that direction. When you write top:50% , the div will be pushed down 50% from the top. You want it to be centered vertically, so you need to counter this by pulling it back up . This can be done using margin-top: -300px just like you used margin-left: -600px to pull it left .

position: absolute;
width: 1200px;
height: 600px;
top: 50%;
margin-top: -300px;
left: 50%;
margin-left: -600px;

Answer 4

top:50%; works fine, but wont "center" the item, it will place it's top edge 50% of the page's height from the top. Similarly to how you have margin-left:-600px; you should also add margin-top:-300px;

Answer 5

You can use

calc(%50 - (items_height/2));

to center.

Answer 6

I believe this may somewhat mimic the answer Kristian gave, but here's my two cents, which includes using percentages and also demonstrates one inside another:

#parent {
    position: absolute;
    top: 50%;
    left: 50%;
    width: 120px;
    height: 60px;
    margin: -60px 0 0 -30px;
    background: blue;
}
#center {
    position: absolute;
    width: 50%;
    height: 50%;
    top: 50%;
    left: 50%;
    margin: -12.5% 0 0 -25%;
    background: green;
}

http://jsfiddle.net/userdude/MYD27/

EDIT

Looking at it further, I think you might run into issues if you're trying to do this with an element not container within a positioned element. For instance:

Full View | Code View

I don't think works the way you intended. When I add position: relative (or alternatively position: absolute ), it does work I think as you intended:

Full View | Code View

Answer 7

I'd like to take this opportunity to blatantly self-promote my answer to another question here on SO :)

That being said, css "top" property gets correctly calculated based on the container element's height - effectively rendering the target element below the midline. What this means is the element needs to be pushed half-way up as explained in the linked question.

Unfortunately such a seemingly straightforward task cannot be accomplished by adjusting top margin etc. without using absolute pixel-based values (+1 for Kristian Antonsen 's answer) - one would imagine setting margin-top to "-50%" would mean just that, but according to css spec, margin values even on the vertical axis are calculated as a percentage always relative to the width of the containing block