Friendly URL like grooveshark/twitter: example.com/#!/whatever
Question
I am trying to get the requested URL from PHP.
The URL is like this: http://example.com/#!/controller/method/var1
I want to get the /controller/method/var1 part from PHP but all I get is http://example.com/
How Grooveshark and Twitter handle this?
1 answers
solution1
2 ACCPTED 2012-03-29 20:55:26
Twitter, Grooveshark and Facebook (before) uses Javascript to get this Friendly URL.
Maybe you can use $_SERVER['REQUEST_URI'] to get it with php, i am not sure.
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