Row-wise count of values that fulfill a condition

Question

I want to generate a new variable which the number of times some columns satisfy a criterion (like == , < , > ). The function needs to handle NA .

Sample data with some missing values:

x <- seq(10, 20)
y <- seq(12, 22)
y[4] <- NA
z <- seq(14, 24)
z[c(4,5)] <- NA
data <- cbind(x, y, z)
#        x  y  z
# [1,]  10 12 14
# [2,]  11 13 15
# [3,]  12 14 16
# [4,]  13 NA NA
# [5,]  14 16 NA
# [6,]  15 17 19
# [7,]  16 18 20
# [8,]  17 19 21
# [9,]  18 20 22
# [10,] 19 21 23
# [11,] 20 22 24

In this example, I want is a variable, "less16", that sums up the number of values in each row that are < 16 , across columns "x", "y" and "z". Desired result for the first few rows:

 x   y   z  less16
10  12  14       3
11  13  15       3
12  14  16       2
13  NA  NA       1
14  16  NA       1
etc

I've tried rowSum , sum , which , for loops using if and else , all to no avail so far. Any advice would be greatly appreciated. Thanks in advance.

Answer 1

rowSums有参数na.rm ：

data$less16 <- rowSums(data < 16, na.rm = TRUE)

Answer 2

许多这些函数实际上都有一个na.rm参数来排除NA值：

apply(data,1,function(x) {sum(x < 16,na.rm = TRUE)})