How to send latest records from database to html texbox after submitting a form?

Question

Steps :
1) select record from database

2) assign record to html textbox

3) user change value in textbox

4) user click "Save" html button.

5) form submit method="post" action="current-page"

6) get value from textbox

7) update record in database table

Explanation : page is refreshed after form submit, so selecting record from db is happened before updating database, that's why html textbox cannot get latest records. How can i assign latest records to textbox after form is submited?

When step 5 is executed, page will refresh. So step 1 and 2 will be executed before step 7, that's why textbox on step 3 cannot get latest record. How to make step 7 happen before step 1?

Problem is solved. I just move up the code of step 7 to on top of step 1.

Answer 1

put an if condition on the same page if form is submitted, update query or when page loads, you can query the latest records

$flag=0;
$submit=$_POST['submit'];
if($submit=="Yes") {
//update database with new value
}
else {
$flag=1;
//query latest value from DB
$latest=$row['latest'];
}

in html form

<input type="text" value="<?php echo $latest; ?>" />

if you don't want the form to be displayed after submit, use the flag

if($flag) { 
//print form
}
else {
// echo data entered
}

Answer 2

You should store temporarily the latest row's unique identifier in your session. That's the easiest way, if your table is not sorted on a way you could achieve it by sorting - like adding an "inserted_time" column with NOW() values and sort by that, get the latest.

Answer 3

I'm not completely sure I understand, but I think mysql_insert_id() might help.

http://www.php.net/manual/en/function.mysql-insert-id.php

After you save the data to the db, grab the last id and use it in your new query.