MVC3: Access a property of an Object in the view

Question

in an ASP.NET MVC3 web application.

I have a view. the view has a IEnumerable model.

I need to loop through all the model's items and show the item.Name

The view:

@model IEnumerable<Object> 
@{
    ViewBag.Title = "Home";
}

@foreach (var item in Model)
{ 
    <div class="itemName">@item.Name</div>
}

In the controller, I use Linq to entities to get the list of objects from the database.

The Controller:

public ActionResult Index()
{
    IEnumerable<Object> AllPersons = GetAllPersons();
    return View(AllSurveys);
}

public IEnumerable<Object> GetAllPersons()
{
    var Context = new DataModel.PrototypeDBEntities();
    var query = from p in Context.Persons
                select new
                {
                    id = p.PersonsId,
                    Name = p.Name,
                    CreatedDate = p.CreatedDate
                };
    return query.ToList();
}

When I run I get this error:

 'object' does not contain a definition for 'Name' and no extension method 'Name' accepting a first argument of type 'object' could be found (are you missing a using directive or an assembly reference?)

How can I access the "Name" Property of the model items?

Thanks a lot for any help

Answer 1

Create a strong type for your method return.

public class MyObject {
    public int id {get;set;}
    public string Name {get;set;}
    public DateTime CreatedDate {get;set;}
}

public IQueryable<MyObject> GetAllPersons() 
{ 
    var Context = new DataModel.PrototypeDBEntities(); 
    var query = from p in Context.Persons 
                select new MyObject
                { 
                    id = p.PersonsId, 
                    Name = p.Name, 
                    CreatedDate = p.CreatedDate 
                }; 
    return query;
} 

... Then update your view to reflect the new model ...

@model IQueryable<MyObject> 

Answer 2

最简单的方法是定义一个Person类，并更改模型/控制器以使用IEnumerable<Person>而不是object。

Answer 3

You probably need to do an explicit Casting

@(string) item.Name

or use dynamic type.

In the view, Change

@model IEnumerable<Object> 

to

@model IEnumerable<dynamic> 

Answer 4

我可能是错的，但您可能尝试使用IEnumerable<dynamic>而不是IEnumerable<Object>

Answer 5

您的模型类型为IEnumerable<Object> ，将其更改为IEnumerable<Person>以便您可以访问Person属性。