I have table
table1
****************************
id | start_date | end_date
1 30/06/2012 01/01/9999
When I insert a new row
id | start_date | end_date
1 30/06/2012 26/06/2012 <- Now it is the start date of the next row2
2 26/06/2012 01/01/9999
The start date of insert row will became the end date of previous row and so on.
$sql = "INSERT INTO
table1(cate_id,task_id,obj,end_date,start_date,line)
SELECT
$cate_id ,
$task_id,
$obj,
'2011-02-28', -> this what I am trying to do
'9999-01-01', -> this what I am trying to do
line1
FROM
line_task
WHERE
line_task_id = (
SELECT
line_task_id
FROM
task
WHERE
task_id = 2
)";
When I tried something like this:
insert into table1(cate_id,task_id,obj, start_date, end_date,line)
values (4,3,23, (Select max(end_date) from table1),end_date,'value_line');
I got message :
Error code 1093, SQL state HY000: You can't specify target table 'table1' for update in FROM clause
Line 1, column 1
Execution finished after 0 s, 1 error(s) occurred
Could told me how can I do this with mysql? Thanks
Try this::
Set @max_date = Select max(end_date) from table;
Insert into table(id, start_date, end_date) values (id, @max_date ,end_date);
First,Get the last record end_date :
$sql = mysql_query("Select * from table1 ORDER BY ID Desc");
if ($row=mysql_fetch_array($sql))
{
$end_date=$row['end_date'];
}
then insert the new record with the previous $end_date.
You can do it in one query
INSERT INTO table1(cate_id,task_id,obj, start_date, end_date,line)
SELECT 4,3,23, MAX(end_date), end_date, 'value_line'
FROM table1;
Just have to follow proper syntax (second example): http://dev.mysql.com/doc/refman/5.5/en/insert-select.html
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