I am using sending an ajax request on php. In form method im using the following code.
rohit1.php
<form action="index1.php" onsubmit="callfunc()">
<span id="raj"></span>
<input type="submit" value="submit"></div>
</FORM>
in javascript im using: callfun.js
function callfunc()
{
var http =new XMLHttpRequest();
var name=prompt('enter name of the form');
var name="rohit";
var url = "index1.php";
var s = document.getElementById('raj').innerHTML;
alert(http);
http.open("POST", "index1.php?name="+name, true);
http.onreadystatechange = function()
{
if(http.readyState == 4 && http.status == 200)
{
}
}
http.send();
}
when i am using this function. then on submit this is redirecting on index.php?label= instead of index.php?name= what should I do for this???
Just try to add return false
at the end of callfunc()
function. It will prevent the form's default event and will not act as a standard form.
<form action="index1.php" onsubmit="callfunc()">
<span id="raj"></span>
<input type="submit" value="submit"></div>
</form>
and the appropriate javascript will look like this:
function callfunc() {
var name = "some name here"; // get this name from whereever you want
window.location.href = "index1.php?name="+name;
return false;
}
this should work for you
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