In the bellow snipet you can see that i am trying to download some data from a website via their API in JSON format.
My problem is that when i try to get the data in json format (25 mb of text data) the php script send me a 200 response (which you can see below). But the weird part is that the script actualy finishes executing and the response is downloaded by my browser as a file.
The url if inputed into browser returns correct data, even via wget i can download the contents from this url.
Could it be that curl will pass through the respose from the server to my browser?
$ch = curl_init("https://example.com/api/json/view/view_name?authtoken=xxxyyyaaaa&raw=true");
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HEADER, false);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
$data = curl_exec ($ch);
downloaded file "myscriptname.php" which contains:
<!DOCTYPE HTML PUBLIC "-//IETF//DTD HTML 2.0//EN">
<html><head>
<title>200 OK</title>
</head><body>
<h1>OK</h1>
<p>The server is temporarily unable to service your
request due to maintenance downtime or capacity
problems. Please try again later.</p>
</body></html>
嗯,这就是您实际使用的cURL optin CURLOPT_RETURNTRANSFER的作用:将传输的内容返回给用户代理。
Your request was OK , but server returned the content as html page (may be their API is not working) so you are getting the maintenance page as reply. looking at php.net
CURLOPT_RETURNTRANSFER TRUE
to return the transfer as a string of the return value of curl_exec()
instead of outputting it out directly.
when i used curl to
<?php
$ch = curl_init("http://localhost/testjson.php");
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HEADER, false);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
$data = curl_exec ($ch);
print_r($data);
?>
what i got after exec is
{"result":["google","stack","facebook"]}
(this is because i printed the result using print_r($data);)
testjson.php is
<?php
$data = array ('result'=>array('google','stack','facebook'));
header('content-type:application/json');
echo json_encode($data);
?>
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