I'm using CodeKit to run jsHint over my scripts, and minimise them, and I'd like to understand the following error:
// create a next button for each text input and wire it for nextQ()!
var next = $('<a class="button next">Next</a>')
.on( 'click', function() {
nextQ( $(this) );
})
.insertAfter( $questions.find(':text') );
jsHint warns:
next is defined but never used
Given that the element is insertedAfter() on each page load, is this a limitation of jsHint, or am I doing something wrong? My jQuery is pretty basic, and I'd like to learn from the error!
Well, you are defining a callback, which doesn't need to be assigned to a variable; you can simply do:
$('<a class="button next">Next</a>')
.on( 'click', function() {
nextQ( $(this) );
})
.insertAfter( $questions.find(':text') );
So next serves no purpose.
The next
var is unnecessary, as .insertAfter()
is called on the return value from .on()
. Unless you're going to call something on next
, you can just do:
$('<a class="button next">Next</a>')
.on( 'click', function() {
nextQ( $(this) );
})
.insertAfter( $questions.find(':text') );
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