Submitting a php pop-up form with javascript

Question

I have a pop up form in php that is opened by javascript. I want this to be sent to my database when I click on submit. The php form works fine without the javascript, but when added it doesn t work. Would you have any idea how to solve this.

 </style>
 <script type='text/javascript'>
 $(document).ready(function() {
  $('#box_form').dialog({
    autoOpen: false,
    height: 375,
    width: 350,
    modal: true,
    buttons: [
        {
        text: "Cancel",
        click: function() {
            $(this).dialog("close");
        }},
    {
        text: "Submit",
        click: function() {
            $('#former').submit();
        }}
    ]
});
$('#clicky').button().click(function(e){
    $('#box_form').dialog('open');
});
  });
    </script>
    </head>
   <body>
   <form id="former" method="post" action="film_post.php" name="former">
  <div id="box_form">
   <select id="option" name="option">
                    <option value="film">film</option>
                    <option value="livre">livre</option>
                    <option value="musique">musique</option>            
            </select></p>
    <p>
    <select id="star" name="star">
                    <option value="1">1</option>
                    <option value="2">2</option>
                    <option value="3">3</option> 

            </select></p>
    <label for="nom">nom</label> :  <input type="text" name="nom" id="nom" /><br />

 </div>
 </form>
 <input type="button" id="clicky" value="Show Form">

and the film_post.php file is:

  try
  {
$bdd = new PDO('mysql:host=localhost;dbname=website', 'root', 'root');
   }
  catch(Exception $e)
 {
    die('Erreur : '.$e->getMessage());
   }

    $option = $_POST['option'];
      $star = $_POST['star'];

    if ($option == film AND $star = 1) {
   $req = $bdd->prepare('INSERT INTO film (film, star) VALUES(?,?)');
     $req->execute(array($_POST['nom'],$_POST['star'] )); }

     elseif ($option == film AND $star = 2) {
    $req = $bdd->prepare('INSERT INTO film (film, star) VALUES(?,?)');
    $req->execute(array($_POST['nom'],$_POST['star'] )); }

     elseif ($option == film AND $star = 3) {
   req = $bdd->prepare('INSERT INTO film (film, star) VALUES(?,?)');
   $req->execute(array($_POST['nom'],$_POST['star'] )); }

Answer 1

Apparently I can't post images yet, so here's a link to the one I have talk about in my answer below. http://i.stack.imgur.com/xgExo.png

I executed your code, grabbing the necessary script src tags, which I assume you have in your actual code, and found the same problem you did. After looking at the firebug console, like jchapa suggested, I found what you can see in the images above.

The jquery ui you are using rewrites your from in such a way that not only does it give it those bubbly graphics but it also terminates your form tag prematurely, as seen where I have underlined the "" text.

How you fix this, I don't know, but that is where your problem lies. You might consider looking online for how to setup a form in this jquery ui or you might just build your own from dialog. Admittedly, though, the graphics won't be quite as sleek.

Submitting a php pop-up form with javascript

Question

1 answers

solution1
0 2012-12-13 01:15:17

Submitting a php pop-up form with javascript

Question

1 answers

solution1 0 2012-12-13 01:15:17

solution1
0 2012-12-13 01:15:17