How to show/hide a form on button click in jquery?
Question
I have two forms in my page. I hide the form 2 using HTML inline style.
<form id="productionForm" name="productionForm" method="POST" style="display:none;">
I have input button on form 1.
<input id="buttonProductionSummary" class="buttonProductionSummary" type="submit" value="Submit" />
I have JQuery code to load the form 2 on button click of form 1. My JQuery code is as follows.
<script type="text/javascript">
$(document).ready(function(){
$("#buttonProductionSummary").click(function() {
$("#productionForm").show();
});
});
</script>
When i click the button in the form one, the page get reloaded again, so the form 2 appears and disappers again. How to can i make the form 2 to appear when i click button on form 1.
4 answers
solution1
3 ACCPTED 2012-12-15 00:24:51
You need to prevent the default behavior of the form:
$("#buttonProductionSummary").click(function(e) {
$("#productionForm").show();
e.preventDefault();
});
solution2
2 2016-12-07 20:25:14
None of the answers above works, so I figured it out myself. This code works like a charm.
<button id="btn" class="editbutton" >Edit your Profile</button>
<form id="editForm" action="" method="post" name="editForm">
<input type="text" name="txtname" placeholder="enter your name">
</form>`
<script type="text/javascript">
$(document).ready(function(){
$("#editForm").hide();
$("#btn").click(function(e) {
$("#editForm").show();
$("#btn").hide();
});
});
</script>
solution3
1 2012-12-15 00:29:26
The problem is that clicking the button in form 1 is triggering a submission of the form (default event)... Hence, the page reloading. You should prevent that by using the submit event as your trigger, handle the form using AJAX and output the result to #productionForm before displaying:
$("#form1").submit(function() {
/* AJAX calls and insertion into #productionForm */
$("#productionForm").show();
return false;
});
solution4
1 2013-12-14 13:46:35
as per my requirement i tried to display the form which is to be edit and hide all remaining forms using the following way;
<html>
<head>
<script>
$(document).ready(function(){
$("#what").click(function() { //event called
$(".hello").hide(); // to hide all forms
$('#ayyappa1').show(); //to dispaly needed form only
return false //option to stop
});
});
</script>
</head>
<body>
<form id ="ayyappa1 " class ="hello"> // declare class for every form
<input type="check" class="what"> // trigger of click event
</form>
<form id ="ayyappa2 " class ="hello">
<input type="check" class="what">
</form>
<form id ="ayyappa3 " class ="hello">
<input type="check" class="what">
</form>
<form id ="ayyappa4 " class ="hello">
<input type="check" class="what">
</form>
</body>
</html>
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