NSArray sort against another NSArray of strings

Question

I feel like this is simple but I just can't wrap my head around it. I have an array of days of the week that a user can select against:

NSArray * daysOfTheWeek = [NSArray arrayWithObjects:@"sunday", @"monday", @"tuesday", @"wednesday", @"thursday", @"friday", @"saturday", nil];

I as the toggle the days on and off, I'd like to sort their NSArray fo selected days against the dayOfTheWeek NSArray. So if a user has:

NSArray * userDays = [NSArray arrayWithObjects:@"thursday", @"monday", @"friday"];

I want to sort this so that its monday, thursday, friday.

I'd seem some of the similar questions posted but none were clear enough for me to know how I could apply them to this. Could be my lack of sleep :)

Thank you!

Answer 1

NSArray *sortedUserDays = [userDays sortedArrayUsingComparator:^(id a, id b) {
    return [@([daysOfTheWeek indexOfObject:a]) compare:@([daysOfTheWeek indexOfObject:b])];
}];

Edit: This sorts the array using a block as a comparator.

To compare two elements of the userDays array it first searches their positions in the template array daysOfTheWeek : [daysOfTheWeek indexOfObject:a]

It then wraps the positions into NSNumbers: @(index) .

Next it calls compare: on the wrapped indices. That's just a lazy way of returning an NSComparisonResult for the two NSUInteger positions.

Answer 2

另一种方法是使用用户选项简单地过滤一周中的几天。

NSArray *sortedUserDays = [daysOfTheWeek filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"SELF in (%@)", userDays]];