I have following scenario: Datepicker for user to choose Year,Month, and use it to display records for the selected month. The selected value is passed to details_subcontractor.php, using Ajax. Datepicker has been modified from accepted answer in jQuery UI DatePicker to show month year only . Sample code as below:
/**
* Datepicker in datepicker.php
*
*/
$("#year_month").datepicker({"dateFormat":"yy-mm-dd",
changeMonth: true,
changeYear: true,
dateFormat: 'yy-mm',
showButtonPanel: true,
onClose: function(dateText, inst) {
var month = $("#ui-datepicker-div .ui-datepicker-month :selected").val();
var year = $("#ui-datepicker-div .ui-datepicker-year :selected").val();
$(this).datepicker('setDate', new Date(year, month, 1));
}
});
/**
* Ajax call
*
*/
var year_month = $("#year_month").val();
$.ajax({
url:"details_subcontractor.php",
data:{
year_month:year_month
},
success:function(data){
$("#content_report").html(data);
}
});
/**
* details_subcontractor.php
*
*/
//$_GET['year_month']; //2012-12
$start = date('Y-m-d', strtotime($_GET['year_month'])); //2012-12-18
$start = date('Y-m-d', strtotime('first day of ' . $_GET['year_month'])); //1970-01-01
$start = date('Y-m-d', strtotime($_GET['year_month'] . ' first day')); //2012-12-19
$end = date('Y-m-d', strtotime('last day of ' . $_GET['year_month'])); //1970-01-01
$end = date('Y-m-d', strtotime($_GET['year_month'] . ' last day')); //2012-12-17
However, as the inline comment shows, I can't get first day and last day of the Month. I'm aware that 'of' is introduced at PHP 5.3, where the 2 lines that contain 'of' are failed, but I don't understand the output of other three. I ended up with appending '-01' and '-31' to indicate first and last day of month. Does anyone have a better solution, that works in PHP 5.2.6?
You can safely assume that the first day of every month is 1
. Use
date('Y-m-t', strtotime($_GET['year_month']));
for the last day of the month.
// The first day is always 01, so you can hardcode it
$start = date('Y-m-01', strtotime($_GET['year_month']));
// last day you can get by `t` format parameter, which contains total days count for given month.
$end = date('Y-m-t', strtotime($_GET['year_month']));
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