I have a class in mongoengine
class Post(EmbeddedDocument):
uid = StringField(required=True)
text = StringField(required=True)
value = StringField()
class Feed(Document):
label = StringField(required=True)
feed_url = StringField(required=True)
posts = ListField(EmbeddedDocumentField(Post))
I am trying to update the Post
EmbeddedDocument
property name text from a certain "Parent" document. As a first step, I retrieve the Feed Document
model = Feed.objects(_id="....").first()
and then I want to update the property text of the embedded document "Post".
How can I achieve it with mongoengine?
我解决了:)
Feed.objects(_id="...", posts__text="findvalue").update(set__posts__S__value="updatevalue")
If I understand the question, I think something like this will work:
model = Feed.objects(_id="....").first()
for post in model.posts:
if post.text == "title":
post.value = "placeholder for real update"
model.save()
Expanding on @hoangvu68's answer. Here is another example: https://gist.github.com/pingwping/92219a8a1e9d44e1dd8a
The format is:
MyModel.objects.find(<model-key> = <model-val>, <embedded-doc-key>__<embedded-doc-lookup-key>=<lookup-key-val>).update(set__<embedded-doc-key>__S__<embedded-doc-lookup-key> = <new-val>)
Note this can be split in 2 lines
doc = MyModel.objects.find(<model-key> = <model-val>, <embedded-doc-key>__<embedded-doc-lookup-key> = <lookup-key-val>)
doc.update(set__<embedded-doc-key>__S__<embedded-doc-lookup-key> = <new-val>)
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