SQL查询有效，但不适用于PHP

Question

我测试并成功使用下面的SQL代码将数据输入数据库。

INSERT INTO hraps (id, firstname, lastname, gender, year_of_1st_rappel, count_offset_proficiency, count_offset_operational, spotter) values(111111, 'World', 'Hello', 'Male', '2007', '1', '2', '0')

现在，我试图像这样将其集成到PHP中：

 $query = "INSERT INTO hraps (firstname, lastname, gender, year_of_1st_rappel, count_offset_proficiency, count_offset_operational, spotter) "
."values('".$this->firstname."','".$this->lastname."','".$this->gender."','".$this->year_of_1st_rappel."',".$this->count_offset_proficiency.",".$this->count_offset_operational.",".$this->spotter.") returning id into :id";

$dbid = "";
$binds = array();
$binds[] = array("name" => ":id", "value" => &$dbid, "length" => 128);
//echo $query;              
$result = mydb::cxn()->query($query, $binds);
$this->id = $dbid;

但是什么也没插入，我没有任何错误。 唯一的区别是，在此代码中，我将id定义为$ dbid，并且在将其硬编码到查询的“ values”部分中之前。

有人可以指出为什么此代码无法成功工作吗？ 谢谢。

Answer 1

只需删除"." 在VALUES之前。 尝试这个

而您错过了mysqli_query()

   $query= "INSERT INTO hraps (firstname, lastname, gender, year_of_1st_rappel, count_offset_proficiency, count_offset_operational, spotter) 
  values ('".$this->firstname."','".$this->lastname."','".$this->gender."','".$this->year_of_1st_rappel."',".$this->count_offset_proficiency.",".$this->count_offset_operational.",".$this->spotter.") returning id into :id ";

编辑：如果它Oracle然后使用此

    $compiled = oci_parse($db, $query); //-- $db is your connection to database variable
    oci_bind_by_name($compiled, ':id', $id);  // --your id
    oci_execute($compiled);

Answer 2

上面的两个查询不相等，因为它们使用不同的数据类型（int v字符串）。

第一个强制转换为字符串，第二个强制转换为int。 将INSERT查询更改为：

$query = "INSERT INTO hraps (firstname, lastname, gender, year_of_1st_rappel, count_offset_proficiency, count_offset_operational, spotter) "
."values('".$this->firstname."','".$this->lastname."','".$this->gender."','".$this->year_of_1st_rappel."','".$this->count_offset_proficiency."','".$this->count_offset_operational."','".$this->spotter."') returning id into :id";`