SQL查詢有效，但不適用於PHP

Question

我測試並成功使用下面的SQL代碼將數據輸入數據庫。

INSERT INTO hraps (id, firstname, lastname, gender, year_of_1st_rappel, count_offset_proficiency, count_offset_operational, spotter) values(111111, 'World', 'Hello', 'Male', '2007', '1', '2', '0')

現在，我試圖像這樣將其集成到PHP中：

 $query = "INSERT INTO hraps (firstname, lastname, gender, year_of_1st_rappel, count_offset_proficiency, count_offset_operational, spotter) "
."values('".$this->firstname."','".$this->lastname."','".$this->gender."','".$this->year_of_1st_rappel."',".$this->count_offset_proficiency.",".$this->count_offset_operational.",".$this->spotter.") returning id into :id";

$dbid = "";
$binds = array();
$binds[] = array("name" => ":id", "value" => &$dbid, "length" => 128);
//echo $query;              
$result = mydb::cxn()->query($query, $binds);
$this->id = $dbid;

但是什么也沒插入，我沒有任何錯誤。 唯一的區別是，在此代碼中，我將id定義為$ dbid，並且在將其硬編碼到查詢的“ values”部分中之前。

有人可以指出為什么此代碼無法成功工作嗎？ 謝謝。

Answer 1

只需刪除"." 在VALUES之前。 嘗試這個

而您錯過了mysqli_query()

   $query= "INSERT INTO hraps (firstname, lastname, gender, year_of_1st_rappel, count_offset_proficiency, count_offset_operational, spotter) 
  values ('".$this->firstname."','".$this->lastname."','".$this->gender."','".$this->year_of_1st_rappel."',".$this->count_offset_proficiency.",".$this->count_offset_operational.",".$this->spotter.") returning id into :id ";

編輯：如果它Oracle然后使用此

    $compiled = oci_parse($db, $query); //-- $db is your connection to database variable
    oci_bind_by_name($compiled, ':id', $id);  // --your id
    oci_execute($compiled);

Answer 2

上面的兩個查詢不相等，因為它們使用不同的數據類型（int v字符串）。

第一個強制轉換為字符串，第二個強制轉換為int。 將INSERT查詢更改為：

$query = "INSERT INTO hraps (firstname, lastname, gender, year_of_1st_rappel, count_offset_proficiency, count_offset_operational, spotter) "
."values('".$this->firstname."','".$this->lastname."','".$this->gender."','".$this->year_of_1st_rappel."','".$this->count_offset_proficiency."','".$this->count_offset_operational."','".$this->spotter."') returning id into :id";`