PHP中的SQL查詢僅在功能外起作用

Question

我有以下PHP代碼段：

function getFacilities($testName, $dbAdapter) {
  $sql1 = "SELECT * FROM facilities_db WHERE facility_name = '$testName'";
  $result1 = $dbAdapter->query($sql1);

  $facility_details = array();
  while ($row = mysqli_fetch_assoc($result1))
  {
    $facility_details[] = $row;
  }
  return $facility_details;
}

$testName = "Abraham Moss Leisure";
$facility_data = getFacilities($testName, $mysqli);

僅出於測試目的，$ testName的值是任意的。 這是答案中的函數，但是我最初的定義的唯一區別是沒有$ dbAdapter作為參數。

Answer 1

您需要將$ testName設置為參數，還要設置將用於獲得與SGBD的連接的適配器（此處為mysqli）。

function getFacilities($testName, $dbAdapter) {
    $sql1 = "SELECT * FROM facilities_db WHERE facility_name = '$testName'";
    $result1 = $dbAdapter->query($sql1);

    $facility_details = array();
    while ($row = mysqli_fetch_assoc($result1))
    {
      $facility_details[] = $row;
    }
    return $facility_details;
}

我們需要將$testName和$mysqli作為您的dbAdapter傳遞給該函數。 因此，這就是我們調用函數的方式：

$facility_data = getFacilities($testName, $dbAdapter);

希望這會有所幫助，

Answer 2

測試查詢結果：

print_r(mysqli_fetch_assoc($result));

測試$mysqli的功能：

function get($testName, $adapter) { if (!isset($adapter)) echo 'no'; }

使用靜態數據庫連接：

class GlobalClass { public static $db = null; }

class Connection {
public $connection = null;
public function connect() {
    if ($connection == null)
        // operation
    $this->connection = 'obj';
}}


$db = new Connection();
$db->connect();
GlobalClass::$db = new Connection();
GlobalClass::$db->connect();
GlobalClass::$db->connection->query($sql);

function yourFunction($testName) {
    $sql1 = "SELECT * FROM facilities_db WHERE facility_name = '$testName'";

    $result1 = GlobalClass::$db->connection->query($sql1);

    $facility_details = array();
    while ($row = mysqli_fetch_assoc($result1)) {
      $facility_details[] = $row;
    }
    return $facility_details;
}

Answer 3

    function getFacilities($testName) {
          global $dbAdapter;
        $sql1 = "SELECT * FROM facilities_db WHERE facility_name = '$testName'";
        $result1 = $dbAdapter->query($sql1);

        $facility_details = array();
        while ($row = mysqli_fetch_assoc($result1))
        {
          $facility_details[] = $row;
        }
        return $facility_details;
    }

$testName = "Abraham Moss Leisure";
$facility_data = getFacilities($testName);

將連接變量聲明為全局變量，並傳遞$ testname的值