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确定通用可比数组的排名

[英]Determine ranking of generic comparable array

如果有此代码(取自https://stackoverflow.com/a/4859279/1178781 ):

import java.util.Comparator;

public class ArrayIndexComparator<T extends Comparable<? super T>> implements
        Comparator<Integer> {
    private final T[] array;

    public ArrayIndexComparator(T[] array) {
        this.array = array;
    }

    public Integer[] createIndexArray() {
        Integer[] indexes = new Integer[array.length];
        for (int i = 0; i < array.length; i++) {
            indexes[i] = i; // Autoboxing
        }
        return indexes;
    }

    @Override
    public int compare(Integer index1, Integer index2) {
        // Autounbox from Integer to int to use as array indexes
        return array[index1].compareTo(array[index2]);
    }
}

当我运行程序时,会发生以下情况:

import java.util.Arrays;
import java.util.Comparator;

public class Launcher {

    /**
     * @param args
     */
    public static void main(String[] args) {
        String[] countries = { "A", "H", "E", "C", "D", "F", "G", "B" };
        ArrayIndexComparator<String> comparator = new ArrayIndexComparator<String>(
                countries);
        Integer[] indexes = comparator.createIndexArray();
        Arrays.sort(indexes, comparator);
        System.out.print("Array:    ");
        System.out.println(Arrays.toString(countries));
        System.out.print("Rankings: ");
        System.out.println(Arrays.toString(indexes));
        System.out.println("");

        final Float[] scores2 = { 2.3f, 0.7f, 1.4f, 1.2f };
        ArrayIndexComparator<Float> comparator2 = new ArrayIndexComparator<Float>(
                scores2);
        indexes = comparator2.createIndexArray();
        Arrays.sort(indexes, comparator2);
        System.out.print("Array:    ");
        System.out.println(Arrays.toString(scores2));
        System.out.print("Rankings: ");
        System.out.println(Arrays.toString(indexes));
        System.out.println("");

        final Integer[] scores3 = { 1, 2, 0, 3 };
        ArrayIndexComparator<Integer> comparator3 = new ArrayIndexComparator<Integer>(
                scores3);
        indexes = comparator3.createIndexArray();
        Arrays.sort(indexes, comparator3);
        System.out.print("Array:    ");
        System.out.println(Arrays.toString(scores3));
        System.out.print("Rankings: ");
        System.out.println(Arrays.toString(indexes));
        System.out.println("");

        final Integer[] scores4 = { 1, 0, 2, 3 };
        ArrayIndexComparator<Integer> comparator4 = new ArrayIndexComparator<Integer>(
                scores4);
        indexes = comparator4.createIndexArray();
        Arrays.sort(indexes, comparator4);
        System.out.print("Array:    ");
        System.out.println(Arrays.toString(scores4));
        System.out.print("Rankings: ");
        System.out.println(Arrays.toString(indexes));
        System.out.println("");

    }

}

输出如下:

Array:    [A, H, E, C, D, F, G, B]
Rankings: [0, 7, 3, 4, 2, 5, 6, 1]

Array:    [2.3, 0.7, 1.4, 1.2]
Rankings: [1, 3, 2, 0]

Array:    [1, 2, 0, 3]
Rankings: [2, 0, 1, 3]

Array:    [1, 0, 2, 3]
Rankings: [1, 0, 2, 3]

我认为这应该正确给出数组中对象的排名,但是某些配置不能这样做。 我想念什么吗? 还是这实际上不是在排序以给出排名,而是其他?

例如:

Array:    [A, H, E, C, D, F, G, B]
Rankings: [0, 7, 3, 4, 2, 5, 6, 1]
Should be:[0, 7, 4, 2, 3, 5, 6, 1]

Array:    [2.3, 0.7, 1.4, 1.2]
Rankings: [1, 3, 2, 0]
Should be:[3, 0, 2, 1]

Array:    [1, 2, 0, 3]
Rankings: [2, 0, 1, 3]
Should be:[1, 2, 0, 3]    

Array:    [1, 0, 2, 3]
Rankings: [1, 0, 2, 3]
Should be:[1, 0, 2, 3]

基于您无需考虑重复的事实,您可以更改周围的所有内容,如下所示:

public static void main(String[] args) {
    String[] countries = { "A", "H", "E", "C", "D", "F", "G", "B" };
    ArrayComparator<String> comparator = new ArrayComparator<String>(
            countries);
    Integer[] indexes = comparator.createIndexArray();
    System.out.print("Array:     ");
    System.out.println(Arrays.toString(countries));
    System.out.print("Rankings: ");
    System.out.println(Arrays.toString(indexes));
    System.out.println("");

    final Float[] scores2 = { 2.3f, 0.7f, 1.4f, 1.2f };
    ArrayComparator<Float> comparator2 = new ArrayComparator<Float>(
            scores2);
    indexes = comparator2.createIndexArray();
    System.out.print("Array:     ");
    System.out.println(Arrays.toString(scores2));
    System.out.print("Rankings: ");
    System.out.println(Arrays.toString(indexes));
    System.out.println("");

    final Integer[] scores3 = { 1, 2, 0, 3 };
    ArrayComparator<Integer> comparator3 = new ArrayComparator<Integer>(
            scores3);
    indexes = comparator3.createIndexArray();
    System.out.print("Array:     ");
    System.out.println(Arrays.toString(scores3));
    System.out.print("Rankings: ");
    System.out.println(Arrays.toString(indexes));
    System.out.println("");

    final Integer[] scores4 = { 1, 0, 2, 3 };
    ArrayComparator<Integer> comparator4 = new ArrayComparator<Integer>(
            scores4);
    indexes = comparator4.createIndexArray();
    System.out.print("Array:     ");
    System.out.println(Arrays.toString(scores4));
    System.out.print("Rankings: ");
    System.out.println(Arrays.toString(indexes));
    System.out.println("");

}

public class ArrayComparator<T extends Comparable<? super T>>{
    private final T[] array;
    private final SortedMap<T, Integer> sortedArray;

    public ArrayComparator(T[] array){
        this.array = array;
        sortedArray = new TreeMap<T, Integer>();
        for(int i = 0 ; i < array.length ; i ++){
            sortedArray.put(array[i], Integer.valueOf(i));
        }
    }

    public Integer[] createIndexArray(){
        Integer[] indexArray = new Integer[sortedArray.size()];
        int i = 0;
        for(T key : sortedArray.keySet()){
            indexArray[sortedArray.get(key)] = i;
            i++;
        }
        return indexArray;
    }
}

然后运行它,您的输出如下所示:

Array:     [A, H, E, C, D, F, G, B]
Rankings:  [0, 7, 4, 2, 3, 5, 6, 1]

Array:     [2.3, 0.7, 1.4, 1.2]
Rankings:  [3, 0, 2, 1]

Array:     [1, 2, 0, 3]
Rankings:  [1, 2, 0, 3]

Array:     [1, 0, 2, 3]
Rankings:  [1, 0, 2, 3]

我相信您正在寻找的东西。

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