[英]How to add variables in SQL
我有一个变量,需要按月显示。 此变量是布尔值,如果将其设置为True,则表示已安装该应用程序。
示例:变量=已安装的应用
一月有20个已安装的应用程序。 2月有10个已安装的应用程序。 3月,安装了5个应用程序。
我想在桌上显示所有已安装的应用程序(布尔值= True):
January: 20
February: 20 (January) + 10 = 30
March: 20 (January) + 10 (February) + 5 (March) = 35
有谁知道如何在Mysql中做到这一点?
谢谢
您可以使用子查询按月对安装进行分组。 然后,您可以在外部查询中使用一个变量来计算累计和:
select installation_year
, installation_month
, installation_count
, (@running_sum:= @running_sum + installation_count) as cumulative_sum
from (
select year(installation_date) as installation_year
, month(installation_date) as installation_month
, count(*) as installation_count
from YourTable
group by
installation_year
, installation_month
) as SubQueryAlias
join (select @running_sum := 0) as InitVars
order by
installation_year
, installation_month
就像是:
Select COUNT(*),Month
From Apps
where installed = true
group by Month
如果我理解正确,那只是一个带有排序依据的简单查询。
select COLUMNS_YOU_WANT from TABLE_NAME
where YOUR_BOOLEAN == True
order by SOME_DATE_COLUMN
希望您精通SQL,可以用所需的内容替换这些部分。
我假设您有一个“应用程序”表,其中包含“已安装”列和“ InstalledDate”列。 如果是这样的话...
SELECT Count(*)
FROM Applications
WHERE Installed = 1 -- Assumes a bit/boolean column.
AND InstalledDate BETWEEN @StartDate AND @EndDate;
史考特
我知道了! 我用了递归
SELECT (select id_time from database.dim_time where id_time = a.fk_time) AS yearmonth, (select sum( if( installed in (1), 1,0)) as installed from database.facts_table where fk_time <= yearmonth ) as installed FROM database.facts_table AS a GROUP BY yearmonth ORDER BY yearmonth ASC
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