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比较匹配的字母并将其存储在两个单词列表中?

[英]Compare and store matching letters in two lists of words?

我是编程的新手,并且在Stackoverflow上阅读了一些有关在两个列表中匹配字符串的问答,但是找不到一个可以帮助我完成此确切任务的问题。

我必须这样列出:

list1 = ["INTP", "ESFJ", "ENTJ"]
list2 = ["ENTP", "ESFP", "ISTJ"]

我想遍历每个单词中的每个字母并存储所有进行的比较,列表中所有单词的匹配字母总数以及匹配的每个字母par,如下所示:

total_letters_compared = 12
total_correct_matches = 8 
first_letter_pair_matches = 1
second_letter_pair_matches = 2
third_letter_pair_matches = 3
fourth_letter_pair_matches = 2

我无法弄清楚如何在两个列表中的某个索引[i]处进行比较,因此我可以以某种方式将匹配项存储在变量中。 到目前为止,我能想到的是:

total = 0
total_letters_compared = 0
total_correct_matches = 0
first_letter_pair_matches = 0
second_letter_pair_matches = 0
third_letter_pair_matches = 0
fourth_letter_pair_matches = 0

for combination in list2:
for letter in combination:
    total_letters_compared = total_letters_compared + 1
    if list2letter == list1.ltter:
        total_correct_matches = total_correct_matches + 1
        # here I´d like to keep track of which letter-pair is compared and
                    # add 1 to the correct variable or continue to the next letter-pair

使用zip来遍历1个以上的集合。 (注意:此代码假定两个列表具有相同数量的项目,并且每个项目都是正确的intp配置文件)

matches = {0:0, 1:0, 2:0, 3:0}

for item1, item2 in zip(list1, list2):
   for i in xrange(4):
      if item1[i]==item2[i]: 
         matches[i] += 1

and you can extract data you want by:

total_letters_compared = #length of a list * 4
total_correct_matches = #sum(matches.values())
nth_letter_pair_matches = #matchs[n-1]

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