[英]Regex matches only a few elements from a list
这是一个python代码段:
import re
VARS='Variables: "OUTPUTFOLDER=installers","SETUP_ORDER=Product 4,Product 4 Library","SUB_CONTENTS=Product 4 Library","SUB_CONTENT_SIZES=9364256","SUB_CONTENT_GROUPS=Product 4 Library","SUB_CONTENT_DESCRIPTIONS=","SUB_CONTENT_GROUP_DESCRIPTIONS=","SUB_DISCS=Product 4,Product Disc",SUB_FILENAMES='
comp = re.findall(r'\w+=".*?"', VARS)
for var in comp:
print var
这是当前的输出:
SUB_CONTENT_DESCRIPTIONS=","
SUB_CONTENT_GROUP_DESCRIPTIONS=","
但是我希望输出提取所有元素,因此看起来像这样:
"OUTPUTFOLDER=installers"
"SETUP_ORDER=Product 4, Product 4 Library"
"SUB_CONTENTS=Product 4"
"SUB_CONTENT_SIZES=9364256"
...
我的正则表达式模式有什么问题?
使用此正则表达式。
comp = re.findall(r'"\w+=.*?"', VARS)
结果:
>>>
"OUTPUTFOLDER=installers"
"SETUP_ORDER=Product 4,Product 4 Library"
"SUB_CONTENTS=Product 4 Library"
"SUB_CONTENT_SIZES=9364256"
"SUB_CONTENT_GROUPS=Product 4 Library"
"SUB_CONTENT_DESCRIPTIONS="
"SUB_CONTENT_GROUP_DESCRIPTIONS="
"SUB_DISCS=Product 4,Product Disc"
我认为,您可以采用更聪明的方式来完成此操作,然后将“ vars”存储在字典中。
d = dict(var.strip('"').split('=') for var in re.findall(r'"\w+=.*?"', VARS))
要查看字典:
for k, v in d.items():
print k, '=', (v if v else '<NONE>')
结果:
>>>
SETUP_ORDER = Product 4,Product 4 Library
SUB_CONTENT_DESCRIPTIONS = <NONE>
SUB_DISCS = Product 4,Product Disc
SUB_CONTENT_GROUPS = Product 4 Library
SUB_CONTENT_SIZES = 9364256
SUB_CONTENT_GROUP_DESCRIPTIONS = <NONE>
OUTPUTFOLDER = installers
SUB_CONTENTS = Product 4 Library
使用此正则表达式:
r'"\w+?=.*?"'
我和您的正则表达式之间的区别,请自己看看:
r'"\w+?=.*?"' # mine
r'\w+=".*?"' # your's
只是一个"
。
输出:
>>> regex = re.compile(r'"\w+?=.*?"')
>>> regex.findall(string)
[u'"OUTPUTFOLDER=installers"', u'"SETUP_ORDER=Product 4,Product 4 Library"',
u'"SUB_CONTENTS=Product 4 Library"', u'"SUB_CONTENT_SIZES=9364256"',
u'"SUB_CONTENT_GROUPS=Product 4 Library"', u'"SUB_DISCS=Product 4,Product Disc"']
您可以尝试以下方法:
comp = re.findall(r'"(.*?)"', VARS)
print [x for x in comp]
大致上,您会以非贪婪的方式获得双引号中包含的所有内容。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.