Django：如何在admin中显示实际对象

Question

我的模型定义如下：

class Artist(models.Model):
    """Model class to record Artist"""
    artist_name = models.CharField(max_length=200)
    artist_id = models.CharField(unique=True, max_length=50)
    # similar relationship is defined.
    related_to = models.ManyToManyField("self", null=True, blank=True)

    def __unicode__(self):
        return self.artist_name

当我对django管理面板中的艺术家使用“删除”管理操作时，我得到：

Artist: trojan

    From_artist-to_artist relationship: Artist_related_to object
    From_artist-to_artist relationship: Artist_related_to object
    From_artist-to_artist relationship: Artist_related_to object
    From_artist-to_artist relationship: Artist_related_to object

Artist: betty

    From_artist-to_artist relationship: Artist_related_to object
    From_artist-to_artist relationship: Artist_related_to object

我如何获得删除期间被警告的实际关系？

换句话说，如何人性化“ Artist_related_to object”以反映实际的艺术家姓名。

Answer 1

您在管理删除问题中看到的是Django透明地为您创建的ManyToMany桥模型的实例。

如果要更改其__unicode__表示形式，则必须定义自己的桥模型，并将ManyToManyField设置为与through参数一起使用。

例：

class ArtistRelationship(models.Model):
    from_artist = models.ForeignKey('Artist')
    to_artist = models.ForeignKey('Artist')

    def __unicode__(self):
        return u"%s - %s" % (self.from_artist.name, self.to_artist.name)


class Artist(models.Model):
    name = models.CharField(max_length=200)
    # ... more fields ...
    related_to = models.ManyToManyField("self", null=True, blank=True,
                                        through=ArtistRelationship)

Answer 2

返回值必须是字符串而不是CharField，请尝试以下操作： return u"%s" % (self.artist_name, )